Answer: A) 45.5N b) 34.6N
Explanation:
Given the following :
Mass of block A(m1) = 5kg
Mass of block B (m2) = 6kg
Angle of incline (Θ) = 45°
Force pulling the down the incline = m1×a×sinΘ
Tension (T) = (m2×a) - (m2)×g
Where g = acceleration due to gravity
a = acceleration
Net force = (5×9.8×sin45°) - (6×9.8)
Net force = 34.648232 - 58.8
The net force acting on the body = 24.4N
Therefore,
Acceleration, a = Net force/ total mass
a = 24.4 / (6+5)
a = 2.22ms^-2
T = (m2 ×g) - (m2×a)
T = (6 × 9.8) - (6 × 2.22)
T = 58.8 - 13.32
T = 45.48
T = 45.5N
B) Normal reaction:
Horizontal component:
m1gCosΘ = 5 × 9.8 × cos45°
= 5 × 9.8 × 0.7071067
= 34.648232
= 34.6N
The tension on the string is 45.62N and the normal force is 34.65N
Data;
m1 = 5.0kgm2 = 6.0kgangle = 45°Tension in The StringTaking the two mass into consideration
for the 6kg mass
[tex]6g - 6a[/tex]
for the 5kg mass
[tex]5gsin45 + 5a\\[/tex]
Equating the tension in both equations
[tex]6g - 6a = 5gsin45 + 5a[/tex]
Let's solve for a
[tex]6a + 5a = 6g - 5gsin45\\11a = 6g - 5gsin45\\a = \frac{6g - 5gsin45}{11}\\ a = \frac{6* 9.8 - 5*9.8*sin45}{11}\\ a = 2.1956 m/s^2\\T = 6g - 6a\\T = 6*9.8 - 6*2.1956\\T = 45.62N[/tex]
b)
The normal force on the 5kg block.
The normal force on the 5kg block can be calculated as
[tex]N = 5 * 9.8 cos 45 = 34.65N[/tex]
The tension on the string is 45.62N and the normal force is 34.65N
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Two projectiles are thrown from the same point with the velocity of49ms-1. First is
projected making an angle with the horizontal and the second at an angle of (90- ). The
second is found to rise 22.5m higher than the first. Find the heights to which each will rise?
Answer:
Height of the first projectile = 49.98 m
Height of the second projectile = 72.52 m
Explanation:
From the given information;
Two projectiles are thrown from the same point with the velocity of49m/s
First is projected making an angle θ with the horizontal
and the second at an angle of 90 - θ.
Thus; for the first height to the horizontal; we have;
[tex]H_1 = \dfrac{v^2 sin^2 \theta}{2g}[/tex] ----- (1)
the second height in the vertical direction is :
[tex]H_2 = \dfrac{v^2 cos^2 \theta}{2g}[/tex] -----(2)
However; the second is found to rise 22.5 m higher than the first; so , we have :
[tex]\dfrac{v^2 cos^2 \theta}{2g}= 22.5 + \dfrac{v^2 sin^2 \theta}{2g}[/tex]
Let's recall that :
Cos²θ = 1 - Sin²θ
Replacing it into above equation; we have:
[tex]\dfrac{v^2}{2g} - \dfrac{v^2 sin^2 \theta}{2g}= 22.5 + \dfrac{v^2 sin^2 \theta}{2g}[/tex]
[tex]\dfrac{v^2}{2g} - 22.5 = \dfrac{v^2 sin^2 \theta}{g}[/tex]
[tex]\dfrac{1}{2 } \dfrac{v^2}{g} - 22.5 = \dfrac{v^2 sin^2 \theta}{g}[/tex]
[tex]\dfrac{1}{2 } - \dfrac {9.8 \times 22.5}{(49)^2} = sin^2 \theta[/tex]
[tex]\dfrac{1}{2 } - \dfrac {220.5}{2401} = sin^2 \theta[/tex]
[tex]sin^2 \theta= 0.408[/tex]
From (1);
[tex]H_1 = \dfrac{v^2 sin^2 \theta}{2g}[/tex]
[tex]H_1 = \dfrac{49^2 \times 0.408}{2*9.8}[/tex]
[tex]H_1 = \dfrac{979.608}{19.6}[/tex]
[tex]\mathbf{H_1 =49.98 \ m }[/tex]
Height of the first projectile = 49.98 m
Similarly;
From(2)
[tex]H_2 = \dfrac{v^2 cos^2 \theta}{2g}[/tex]
[tex]H_2 = \dfrac{v^2 (1-sin^2 \theta)}{2g}[/tex]
[tex]H_2 = \dfrac{49^2 (1-0.408 )}{2 \times 9.8}[/tex]
[tex]H_2 = \dfrac{2401 (0.592 )}{19.6}[/tex]
[tex]H_2 = \dfrac{1421.392}{19.6}[/tex]
[tex]\mathbf{H_2 = 72.52 \ m}[/tex]
Height of the second projectile = 72.52 m
What does FAI stand for?
Answer:
Femoroacetabular impingement
It occurs when an area of your hip joint becomes pinched when you move in certain directions. :)
For the following elementary reaction 2br• -> br2-. The rate of consumption of the reaction and the rate of formation of product is given by which set of expression?
Answer: [tex]-\frac{1}{2}\times \frac{d[Br^.]}{dt}=+\frac{d[Br_2]}{dt}[/tex]
Explanation:
Rate of a reaction is defined as the rate of change of concentration per unit time.
Thus for reaction:
[tex]2Br^.\rightarrow Br_2[/tex]
The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.
[tex]Rate=-\frac{d[Br^.]}{2dt}[/tex]
or [tex]Rate=+\frac{d[Br_2]}{dt}[/tex]
Thus [tex]-\frac{d[Br^.]}{2dt}=+\frac{d[Br_2]}{dt}[/tex]
A ball is being rolled by a normal push of 180N. It is opposed by friction which has a force of 61N and air resistance which has a force of 23N. Calculate the resultant force.
Resultant force is basically the force left after everything is added.
if a ball is being pushed one one side with 180N, and being pushed on teh opposite side with 84N (I added friction and air resistance since they're acting on the same side), then the resultant force would be:
180N - 84N = 96N (you can determine whether it's positive or negative based on the direction of the vector)
What engineering problem was presented in the study?
A. The lightbulbs were too bright.
B. The lightbulbs were too dim.
C: The lightbulbs were exploding after several minutes of use.
D. The lightbulbs were burning out after only a few hours of use.
Answer:
The lightbulbs were exploding after several mins of use
Explanation:
Answer:
the lightbulbs were exploding after several minutes of use
Explanation:
a p e x :))
Which of the following is an example of the Doppler effect? A water bug on the surface of a pond is producing small ripples in the water. The bug is not moving. A police car with its siren on is driving towards you, and you perceive the pitch of the siren to increase. Scientists measure the speed of light and find that it is constant. The gravitational pull of two objects on each other
Answer:
A police car with its siren on is driving towards you, and you perceive the pitch of the siren to increase.
Explanation:
In Physics, Doppler effect can be defined as the change in frequency of a wave with respect to an observer in motion and moving relative to the source of the wave.
Simply stated, Doppler effect is the change in wave frequency as a result of the relative motion existing between a wave source and its observer.
The term "Doppler effect" was named after an Austrian mathematician and physicist known as Christian Johann Doppler while studying the starlight in relation to the movement of stars.
The phenomenon of Doppler effects is generally applicable to both sound and light.
An example of the Doppler effect is a police car with its siren on is driving towards you, and you perceive the pitch of the siren to increase. This is so because when a sound object moves towards you, its sound waves frequency increases, thereby causing a higher pitch. However, if the sound object is moving away from the observer, it's sound waves frequency decreases and thus resulting in a lower pitch.
Other fields were the Doppler effects are applied are; astronomy, flow management, vibration measurement, radars, satellite communications etc.
Answer:
A police car with its siren on is driving towards you, and you perceive the pitch of the siren to increase.
Explanation:
This should be the correct answer.
a) Under what circumstances would a constant force result in increasing acceleration on a body? b) Under what circumstances would a constant force result in zero acceleration on a body?
Answer:
Remember the equation:
F = m*a
where F is force, m is mass and a is acceleration.
If we have F constant. and we want that increases, then we can have the case where m decreases.
The mass can decrease in cases like a rocket, where as the fuel of the rocket consumes, the mass of the rocket decreases and the acceleration increases.
b) The cases where a constant force results in a constant acceleration of zero, is when the force is canceled, an example of this is the constant force of the gravity in all the objects. The objects that are in the ground are being affected by this force, but the gravitational force is canceled with the normal force of the ground. Then we have a constant force that does not cause any acceleration.
A body accelerate uniformly from rest at 0.2m/s for one-fifth of a minute. Calculate the distance covered by the body.
Answer:
14.4 mThe distance covered by the body is 14.4 m.
Solution,
Initial velocity(u)= 0 m/s( according to Question, the body starts from rest.that's why initial velocity(u) becomes zero.
Acceleration (a)= 0.2 m/s
Time (t):
[tex] \frac{1}{5} minute = \frac{1}{5 } \times 60 \: seconds[/tex]
[tex] = 12 \: seconds[/tex]
Now,
Applying third equations of motion:
[tex]s = ut + \frac{1}{2} a {t}^{2} \\ s = 0 \times 12 + \frac{1}{2} \times 0.2 \times {(12)}^{2} \\s = 0 + 14.4 \\ s = 14.4 \: metre[/tex]
Thus, the distance covered by the body is 14.4 metre.
Further more information:
Application of equation of motion in different situation:When a certain object comes in motion from rest, in the case, initial velocity(u)= 0 m/sWhen a moving object comes in rest,in the case, final velocity(v)= 0 m/sIf the object is moving with uniform velocity, in the case, (u=v)If any object is thrown vertically upward, in the case, acceleration (a)= -gWhen an object is falling from certain height, in the case, u= 0 m/sWhen an object is thrown vertically upwards in the case, final velocity at maximum height becomes 0.The magnitude of the electric potential depends on which factors?
O A. Mass and amount of charge
O B. Mass and distance
O C. Distance and amount of charge
O D. Density and amount of charge
Answer:
C
Explanation:
It is directly propotional to the amount of charge and inversly propotional to distance.
Answer:
C. Distance and amount of charge
Explanation:
The magnitude of the electric potential depends on which factors?
Distance and amount of charge
What is the momentum of a 35.0 kg cannonball fired from a cannon with a velocity of 500.0 m/s?
Answer:
p = 17500 kg*m/s
Explanation:
p = mv
p = 35.0 kg * 500.0 m/s = 17500 kg*m/s
The momentum of a 35.0 kg cannonball fired from a cannon with a velocity of 500.0 m/s will be equal to 17500 [tex]\dfrac{kg.m}{s}[/tex]
What is momentum ?
When any body which is having a mass and is in the motion carry momentum with it.
The formula for finding the momentum of any body is given by
[tex]Momentum = Mass\times Velocity[/tex]
Given that-
[tex]Mass = 35 kg[/tex]
[tex]Velocity = 500[/tex] [tex]\dfrac{m}{s}[/tex]
[tex]Momentum = 35\times500[/tex]
[tex]momentum= 17500 \dfrac{kg.m}{s}[/tex]
Hence The momentum of a 35.0 kg cannonball fired from a cannon with a velocity of 500.0 m/s will be equal to 17500 [tex]\dfrac{kg.m}{s}[/tex]
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A Jaguar XK8 convertible has an eight-cylinder engine. At the beginning of its compression stroke, one of the cylinders contains 499cm3499cm 3 of air at atmospheric pressure (1.01×105Pa)(1.01×10 5 Pa) and a temperature of 27.0∘C27.0 ∘C. At the end of the stroke, the air has been compressed to a volume of 46.2cm 346.2cm 3 and the gauge pressure has increased to 2.72×106Pa2.72×10 6Pa. Compute the final temperature.
Answer:
503°C
Explanation:
According to the given situation, the computation of the final temperature is shown below:
In this question we use the law of ideal gas i.e
pV = nRT
i.e
[tex]\frac{p_1V_1}{T_1} = \frac{p_2V_2}{T_2}[/tex]
Therefore
[tex]T_2 = T_1 (\frac{p_2}{p_1}) (\frac{V_2}{V_1})[/tex]
[tex]= 300\ k (\frac{2.72 \times 10^{6} Pa + 1.01 \times 10^{5} Pa}{1.01 \times 10^{5} Pa})(\frac{46.2 cm^3}{499 cm^3})[/tex]
= 776 k
= (776 - 273)° C
= 503°C
Therefore the final temperature is 503°C
We simply applied the above formulas so that the final temperature could arrive
an astronaut is said to be weightless when he/she travels in a satellite.does it mean that the earth does not attract him/her?
Answer:
No, gravitational force is a force having infinite range. It only reduces to an extent that astronauts cannot feel it.
Explanation:
Rachel and Andrew are riding on a ferry boat traveling east at 3.5 m/s. Rachel rolls a marble with a velocity of 0.95 m/s north, straight across the deck of the boat to Andrew. What is the velocity of the marble relative to the water?
Answer:
The velocity of the marble relative to the water is 3.63 m/s
Explanation:
The information given are;
The velocity of the ferry relative to the water = 3.5 m/s
Direction of motion of the ferry = East
The velocity of the marble (on the ferry) relative to the ferry = 0.95 m/s
The direction of the marble = North
The (resultant) velocity of the marble relative to the water, [tex]v_R[/tex], is found as follows;
Resolution of the velocities;
Velocity of the ferry = 3.5·i + 0·j
Velocity of the marble = 0·i + 0.95·j
[tex]v_R[/tex] = Combined (resultant) velocity = √(3.5² + 0.95²) = 3.63 m/s
The velocity of the marble relative to the water = 3.63 m/s.
An object has a mass of 785g and a volume of 15cm cubed what is its density
Answer:
we have ,
mass(m)=785g
volume (v)= 15 cm^3
now , density(d)= m/ v
=785/15
=52.33g/cm^3... is anwer
A 0.300 kg mass is attached to
a 26.6 N/m spring. It is pulled
0.120 m and released. How much
Kinetic Energy does it have when it
is 0.0600 m from equilibrium?
(Unit = J)
Answer:
0.144 J
Explanation:
From the question above,
Total elastic energy of the spring = Kinetic energy of the spring + potential energy of the spring
E' = E.k+Ep...................... Equation 1
Ek = E'-Ep......................... Equation 2
Where E' = total elastic energy, E.k = kinetic energy, E.p = potential energy.
E' = 1/2ke² = 1/2(26.6)(0.12²) = 0.19152 J.
Ep = 1/2ke² = 1/2(26.6)(0.06²)
Ep = 0.04788 J
Therefore,
Ek = 0.19152-0.04788
Ek = 0.144 J
I just realized my answer was incorrect but I don’t know how to delete an answer.
An object of mass 800g hangs on a spring. Calculate the force exerted by the object if acceleration due to gravity is 10/s2
Answer:
8 N
Explanation:
Using the equation F=ma (F: force/ m: mass in kg/ a: acceleration),
F = (800/1000)(10)
F = 8 N
A locomotive moved 18.0 m [W] in a time of 6.00 s and stopped. After stopping, the locomotive moved 12.0 m [E] in 10.0 s. a. Determine the distance travelled by the locomotive. Show your work.
b. Determine the displacement of the locomotive. Show your work.
Answer:
a) The distance travelled by the the locomotive is 30 meters, b) The final displacement of the locomotive is 6 meters westwards.
Explanation:
a) The distance travelled is the sum of magnitudes of distances covered by the train during its motion. That is to say:
[tex]s_{T} = 18\,m + 12\,m[/tex]
[tex]s_{T} = 30\,m[/tex]
The distance travelled by the the locomotive is 30 meters.
b) The displacement is the vectorial distance of the train with respect to a point of reference, since west and east are antiparallel to each other, calculations can be simplified to a scalar form. Let suppose that movement to the east is positive. The calculations are presented below:
[tex]s_{P} = -18\,m +12\,m[/tex]
[tex]s_{P} = -6\,m[/tex]
The final displacement of the locomotive is 6 meters westwards.
Answer:
the dispalcement is 6m and distance travelled is 30m
Explanation:
Choose all correct statements: Refractive index of medium A with respect to medium B is 4/3 and refractive index of medium A with respect to medium C is 3/2. Medium B is denser than medium C When light travels from B to C light bends away from the normal Refractive index of C with respect to B is 8/9 Ratio of speed of light in medium B to the speed of light in medium A = 4/3
Answer:
Medium B is denser than medium C
When light travels from B to C light bends away from the normal .
Refractive index of C with respect to B is 8/9
Ratio of speed of light in medium B to the speed of light in medium A = 4/3
Explanation:
Refractive index of medium A / Refractive index of medium B = 4/3
Refractive index of medium A / Refractive index of medium C = 3/2
Dividing ,
Refractive index of medium B / Refractive index of medium C
= 3/2 x 3/4
= 9 / 8
Refractive index of medium B > Refractive index of medium C
Refractive index of C with respect to B is 8/9
speed of light in medium B / the speed of light in medium A
= refractive index of A / refractive index of B = 4 / 3
identify units for volts
Answer:
Volts itself is SI Unit of Electric Potential.
Explanation:
A 13,500 kg railroad freight car travels on a level track at a speed of 4.5 m/s. It collides and couples with a 25,000 kg second car, initially at rest and with brakes released. What is the speed of the two cars after collision?
Answer:
V = 1.578m/s
Explanation:
(Ma x Ua) + (Mb x Ub) = (Ma + Mb)V
(13500 x 4.5) + (25000 x 0) = (13500 + 25000)V
60750 + 0 = (38500)V
60750 = 38500V
V = 60750/38500
V = 1.578m/s
The speed of the two cars after the collision will be equal to V = 1.578m/s
What is collision?A collision is any event in which two or more bodies exert forces on each other in a relatively short time. Although the most common use of the word collision refers to incidents in which two or more objects collide with great force, the scientific use of the term implies nothing about the magnitude of the force
Now from the perfectly inelastic collision, the conservation of momentum will be
(Ma x Ua) + (Mb x Ub) = (Ma + Mb)V
(13500 x 4.5) + (25000 x 0) = (13500 + 25000)V
60750 + 0 = (38500)V
60750 = 38500V
V = 60750/38500
V = 1.578m/s
Hence the speed of the two cars after the collision will be equal to V = 1.578m/s
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Un avión vuela a una velocidad de 900 km/h. Si tarda en viajar desde Canarias hasta la península 180 s ¿qué distancia recorre en ese tiempo?
Answer:
El avión recorrió 45 km en los 180 s.
Explanation:
La relación entre velocidad, distancia y tiempo se da de la siguiente manera;
[tex]Velocidad= \dfrac{Distancia}{Hora}[/tex]
Por lo cual los parámetros dados son los siguientes;
Velocidad = 900 km/h = 250 m / s
Tiempo = 180 s
Estamos obligados a calcular la distancia recorrida
De la ecuación para la velocidad dada arriba, tenemos;
Distancia recorrida = Velocidad pf viaje × Tiempo de viaje
Distancia recorrida = 900 km/h × 180 s = 900
Distancia recorrida = 900 km/h × 1 h/60 min × 1 min/60 s × 180 s = 45 km
Por lo tanto, el avión viajó 45 km en 180 s.
Assessment started: undefined. Item 1 Which statement accurately describes what happens when ice melts in terms of energy? A:The ice releases energy which causes chemical bonds to break, changing the ice to water.;B:The ice releases energy which causes the water molecules to have less kinetic and potential energy, changing their configuration from solid to liquid. C:The ice absorbs energy which causes the water molecules to have more kinetic and potential energy, changing their configuration from a solid to a liquid. D:The ice absorbs energy which causes chemical bonds to break, changing ice to water.
Answer:
A.
Explanation:
it's needed top release energy due to the breaking of chemical bonds.
Answer:
A: the ice releases energy which causes chemical bonds to break, changing the water to ice.
Explanation:
100 POINTS! I will mark brainliest! Record your hypothesis as an “if, then” statement for the rate of dissolving the compounds: Record your hypothesis as an “if, then” statement for the boiling point of the compounds:
Answer:
Rate of dissolving compounds:
If we increase the temperature of the solution, then the dissolving compound would dissolve more easily.
Boiling Point of Compounds:
If the inter-molecular forces of any compound is really strong, then the boiling point of the compound would be really high.
Answer: This is just re worded from the other answer to give a different saying to the responce.
Record your hypothesis as an “if, then” statement for the rate of dissolving the compounds: If we increase the temperature then the compound will dissolve easier.
Record your hypothesis as an “if, then” statement for the boiling point of the compounds: If the forces of the compound itself is strong, then the boiling point would be way higher.
In physics what does 7.56 × 5.746 equal ?
Answer:
43.43
Explanation:
5.746 x 7.56 = 43.43976
As the least number of desimal is two so our awnser should contain two digits after the decimal point.
Ans: 43.43.
Answer:
43.4 (Plato/Edmentum)
Explanation:
#1: 7.56 * 5.746
#2: 43.43976
#3: 43.4
I need a story about kepler's laws for a child, something a child would understand. And i'd like it to be okay for someone if I copy anhd paste it or else my parents are gonna kill me and my teacher will be very disappointe, this is for summer school.
Answer:
(1) The orbits are ellipses, with focal points ƒ1 and ƒ2 for the first planet and ƒ1 and ƒ3 for the second planet. The Sun is placed in focal point ƒ1.
(2) The two shaded sectors A1 and A2 have the same surface area and the time for planet 1 to cover segment A1 is equal to the time to cover segment A2.
(3) The total orbit times for planet 1 and planet 2 have a ratio a13/2 : a23/2
Answer:
g the day off and I will be there at work and I will be there at work and I will
Explanation:
you are not going to be able to make it to the meeting tonight but I can tomorrow
A bear can cover 60 min 4 seconds. What speed can it travel?
A. 25 m/s
B. 12 m/s
C. 15 m/s
D. 20 m/s
Answer:
C.15m/s
Explanation:
60 divided by 4 is 15
If a locomotive uses steam at
100°C, and dumps heat into air
at 220°C. what is the highest
possible efficiency it could have?
Answer:
79%
Explanation:
The following data were obtained from the question:
Input temperature = 100°C
Output temperature = 22°C
Efficiency =.?
Next, we shall convert the temperature from celsius to Kelvin temperature. This is illustrated below:
T (K) = T (°C) + 273
Input temperature = 100°C
Input temperature = 100°C + 273 = 373K
Output temperature = 22°C
Output temperature = 22°C + 273 = 295K
The efficiency of the locomotive can be obtained as follow:
Input temperature = 373K
Output temperature = 295K
Efficiency =.?
Efficiency = output /input x 100
Efficiency = 295/373 x 100
Efficiency = 79%
Therefore, the efficiency of the locomotive is 79%.
A roller coaster starts with a speed of 4.6 m/s at a point 49 m above the bottom of a dip.
Neglecting friction, what will be the speed of the roller coaster at the top of the next
slope, which is 29 m above the bottom of the dip?
Answer:
20.5m/s
Explanation:
neglecting friction the amount of energy at the bottom equals to the amount of energy at top. Law of conservation of energy.
ME= P.E+k.E
ME= mgh+ 1/2mv*v
ME = (m* 10 *49)+(1/2m(4.6*4.6))
MEtop=500.98m
MEbottom=MEtop: in order to obey the law of conservation of energy
MEbottom=mgh+ 1/2mv*v
500.98m=m*10*29+1/2m v* v
500.98m= m(290+1/2v*v) ...cancel m by m
500.98-290=1/2v*v criss cross multiple
210.98*2=v*v
v=√421.96
v=20.5 m/s
Answer the following questions regarding the equation:
N₂ + 3H₂ → 2NH₃
1) indicates what type of reaction is
2) what represents the coefficients 3 and 2 in the previous reaction is done for
3) What would be missing in the previous equation to make it more accurate is
Explanation:
1) This is a synthesis reaction (two or more reactants combine to form a single product).
2) The coefficients are added to balance the reaction.
3) Adding the states of matter (solid, liquid, gas) will make the reaction more precise.
What us meant by Velocity ratio of simple machine is 4?