Answer:
a
Explanation:
as the law of conservation of matter (mass) states: matter can not be created nor destroyed but can transform from a form to another.
since the conversion of mass to energy can not be done except in nuclear reactions via (E= mc2). normal chemical equations must be balanced to achieve the law.
A self-aldol or crossed aldol reaction REQUIRES a(n) ___________________. Group of answer choices strong acid only a very, very strong base, such as LDA (lithium diisopropyl amide), NaOH or LiOH won't work acid catalyst a strong base such as LiOH or NaOH
Answer:
[tex]\mathbf{a \ strong \ base \ such \ as\ LiOH \ or \ NaOH.}[/tex]
Explanation:
In the condensation reactions of carbonyl compounds, it is essential to establish the order of events in advance to minimize or suppress the possibilities of self-condensation and the occurrence of cross-condensation, which unfortunately are an obvious threat in these reactions.
Self-condensation:
Any carbonyl compound that has one or more alpha hydrogens, on the carbons adjacent to the carbonyl group, runs the risk of undergoing a self-condensation reaction if the corresponding rigor is not carried out.
Cross-condensation:
Ideally, in the condensation reactions of carbonyl compounds, one of the reacting molecules should quickly enolise, while the other preferably should not have Hα, to ensure that no other by-products are formed.
[tex]\text{To achieve this process;}[/tex] [tex]\text{A self-aldol or crossed aldol requires a strong base such as LiOH or NaOH.}[/tex]
_BaS + _PtF2 → _BaF2 + _Pts
[tex]\huge\underline\mathbb\pink{ANSWER\::}\\\\[/tex]
_BaS + _PtF2 → _BaF2 + _Pts
Barium Sulfide + Platinum(II) Fluoride = Barium Fluoride + Platinum(II) Sulfide.
=> 1 BaS + 1 PtF2 → 1 BaF2 + 1 PtS
[tex]\\\\\\[/tex]
HOPE IT HELPS
PLEASE MARK ME BRAINLIEST☺️
in the ideal gas law which variable represents the gas constant?
a: T
b: R
c: n
d: V
e: P
Explanation:
It is represented using the ideal gas equation , or PV = nRT, where P is the pressure in atmospheres, V is the volume in liters, n represents the quantity of particles in the container, T represents the temperature in Kelvin, and R is the ideal gas constant equal to 0.0821 liters atmospheres per moles Kelvin.
Knowing that Boyle's Law is P1V1 = P2V2, How would we rearrange the formula if we needed to solve for P1?
A. P1 = V1 -P2
B. P1 = P2V2 - V1
C. P1 = P2V2/V1
D. P1= V1/V2
Answer:
your answer is C
Explanation:
because when u make P1 the subject formula then P2 V2 will be divided with V1
Help pleaseeeeeee
Using your knowledge of alpha beta and Gamma decay and your periodic table practice using your ideas by completing the following equations
Answer:
20. ²⁴¹₉₅Am —> ²³⁷₉₃Np + ⁴₂He
21. ⁴²₁₉K —> ⁰₋₁β + ⁴²₂₀Ca
Explanation:
20. ²⁴¹₉₅Am —> __ + ⁴₂He
Let ⁿₘX be the unknown.
Thus, the equation becomes:
²⁴¹₉₅Am —> ⁿₘX + ⁴₂He
Next, we shall determine n, m and X. This can be obtained as follow:
241 = n + 4
Collect like terms
n = 241 – 4
n = 237
95 = m + 2
Collect like terms
m = 95 – 2
m = 93
Thus,
ⁿₘX => ²³⁷₉₃X => ²³⁷₉₃Np
Therefore, the complete equation is:
²⁴¹₉₅Am —> ²³⁷₉₃Np + ⁴₂He
21. __ —> ⁰₋₁β + ⁴²₂₀Ca
Let ʸₓZ be the unknown.
Thus, the equation becomes:
ʸₓZ —> ⁰₋₁β + ⁴²₂₀Ca
Next, we shall determine y, x and Z. This can be obtained as follow:
y = 0 + 42
y = 42
x = –1 + 20
x = 19
Thus,
ʸₓZ => ⁴²₁₉Z => ⁴²₁₉K
Therefore, the complete equation is:
⁴²₁₉K —> ⁰₋₁β + ⁴²₂₀Ca
8. A liquid boils when the vapor pressure of the liquid equals the atmospheric pressure on the surface
of the liquid. Using Reference Table H, determine the boiling point of water when the atmospheric
pressure is 90. kPa
Answer:
It is 98 degrees C.
Explanation:
I NEED HELP PLS ;-; !!!!
Identify the number of electrons each of the following atoms needs to gain or lose to have a stable outer electron configuration.
a. sodium (Na)
b. strontium (Sr)
c. sulfur (S)
d. astatine (As)
A(n) ____________ is a push or a pull.
newton
acceleration
force
momentum
What are Renewable Resoures?
Answer:
resources that you can use more than 1 time like rechargeable battery or solar energy
Explanation:
why does ocean water found near the poles often have a higher leaves of salinity than ocean water found near the equator
The ocean water found near the poles has a higher level of salinity because the area of rain reduces as one moves toward the poles, and as a result of less rain and more sunshine, evaporation increases.
What is salinity?Salinity is the presence of salt in the water. Freshwater bodies have very less amount of salt, but ocean water has a large amount of salt dissolved in it.
Because cold polar air cools the water and decreases its temperature, raising its salinity, water close to the poles frequently has more salinity. When fresh water freezes out of seawater to form sea ice, the salinity of the remaining water likewise rises.
Therefore, as one travels toward the poles, the area of rain decreases, and as a result of less rain and more sunshine, evaporation increases, and the ocean water there has a higher level of salinity.
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FIRST CORRECT ANSWER GETS 10 POINTS!!!!
Which explains how the nervous system is typically involved in keeping the body in homeostasis?
It processes the environment and sends out signals.
It controls movement and provides structure.
It physically breaks down and absorbs food.
It puts oxygen in the blood, which is essential for life.
Answer:
Explanation:
It processes the environment and sends out signals.
A student said, "You can't see the full Moon during the day because it rises close to sunset."
Which diagram supports this statement? (Diagrams are not to scale. You are looking down from
a north polar view fisa person standing on Earth at sunset.)
Oq. Ooo
Ooo
OD
ОА
OB
ОС
OD
Answer:
I think it would be B.
Explanation:
Question #37.P.2A.2
Which statement about the periodic table is true?
a. Elements in the same column share similar properties.
b. Elements in the same row share similar properties.
c. Elements on the left have a larger nucleus than elements on the right.
d. Elements at the top of each column have the highest atomic mass in that column.
Calculate how many moles of NO2 form when each
quantity of reactant completely reacts.
2 N2O5(9) + 4NO2(g) + O2(9)
Part B
6.4 mol N205
Express your answer using two significant figures.
VALO
n =
Submit
Request Answer
Part C
16.2 g N205
Express your answer using three significant figurer
Answer:
partB: n=2N205
partc:17.20
How many moles of gold atoms do 3.45x10^24 gold atoms constitute?
Answer:
3.45E24
Explanation:
calculator I'm not that great at math but I'm good at science but that isn't really science but it's aix between it tho
The purification of hydrogen gas by diffusion through a palladium sheet was discussed in Section 5.3. Compute the number of kilograms of hydrogen that pass per hour through a 5-mm-thick sheet of palladium having an area of 0.20 m2 at 500C. Assume a diffusion coefficient of 1.0 108 m2 /s, that the concentrations at the high- and low-pressure sides of the plate are 2.4 and 0.6 kg of hydrogen per cubic meter of palladium, and that steady-state conditions have been attained
This question is incomplete, the complete question is;
The purification of hydrogen gas by diffusion through a palladium sheet was discussed in Section 5.3. Compute the number of kilograms of hydrogen that pass per hour through a 5-mm-thick sheet of palladium having an area of 0.20 m² at 500C.
Assume a diffusion coefficient of 1.0 × 10⁻⁸ m²/s, that the concentrations at the high- and low-pressure sides of the plate are 2.4 and 0.6 kg of hydrogen per cubic meter of palladium, and that steady-state conditions have been attained
Answer:
the number of kilograms of hydrogen that pass per hour through is 2.592 × 10⁻³ kg
Explanation:
Given the data in the question;
thickness of sheet t = 5 mm
Area A = 0.20 m²
Temperature T = 500°C
diffusion coefficient ∝ = 1.0 × 10⁻⁸ m²/s
concentration high pressure side C[tex]_A[/tex] = 2.4
concentration low pressure side C[tex]_B[/tex] = 0.6 kg
from the question, we calculate the concentration gradient
dc/dx = (C[tex]_A[/tex] - C[tex]_B[/tex])/dt
so we substitute
dc/dx = (2.4 - 0.6) / ( - 5 × 10⁻³ )
dc/dx = -360
now, mass of hydrogen per hour that diffuse through a pd sheet
M = -∝AT(dc/dx)
where time t is 1 hour ( 3600 sec )
we substitute
M = -(1.0 × 10⁻⁸) × 0.20 × 3600 (-360)
M = 0.002592
M = 2.592 × 10⁻³ kg per one hour
Therefore, the number of kilograms of hydrogen that pass per hour through is 2.592 × 10⁻³ kg
The number of kilograms of hydrogen that pass per hour through a 5-mm-thick sheet of palladium having an area of 0.20 m² at 500°C is 2.592 × 10⁻³ kg.
Purification: It refers to the process of removing impurities or contaminants from a substance in order to make it cleaner, purer, or more refined. It also involves the elimination or reduction of unwanted substances or components that may be present in the original material.
According to the question, given data is:
Thickness of sheet t = 5 mm
Area A = 0.20 m²
Temperature T = 500°C
Diffusion coefficient ∝ = 1.0 × 10⁻⁸ m²/s
Concentration high pressure side [tex]C_A[/tex] = 2.4
Concentration low pressure side[tex]C_B[/tex]= 0.6 kg
from the question, we calculate the concentration gradient,
[tex]dc/dx = (C _A- C_B)/dt[/tex]
so, we substitute the values,
[tex]dc/dx[/tex] = (2.4 - 0.6)/ ( - 5 × 10⁻³)
[tex]dc/dx = -360[/tex]
Now, mass of hydrogen per hour that diffuse through a Palladium sheet,
M = -∝[tex]AT(dc/dx)[/tex]
where time t is 1 hour (3600 sec)
We substitute,
M = -(1.0 × 10⁻⁸) × 0.20 × 3600 (-360)
M = 0.002592
M = 2.592 × 10⁻³ kg per hour.
Therefore, the number of kilograms of hydrogen that pass per hour through a palladium sheet is approximately 2.592 × 10⁻³ kg.
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This question is incomplete, the complete question is;
The purification of hydrogen gas by diffusion through a palladium sheet was discussed in Section 5.3. Compute the number of kilograms of hydrogen that pass per hour through a 5-mm-thick sheet of palladium having an area of 0.20 m² at 500C.
Assume a diffusion coefficient of 1.0 × 10⁻⁸ m²/s, that the concentrations at the high- and low-pressure sides of the plate are 2.4 and 0.6 kg of hydrogen per cubic meter of palladium, and that steady-state conditions have been attained.
1. Which kingdom is made up of only autotrophs?
A. Protista
I
B. Animalia
C. Plantae
D. Phylum
Answer: I believe it's C
Hope this helped<3
Can you please make my answer brainly
Which of the following is the correct definition of "weathering"? *
The movement of rocks
The breakdown of rocks.
The dropping off of rocks
All of the above
Which of the following is the Brønsted-Lowry definition of an acid?
Answer:
A Brønsted-Lowry acid is any species that can donate a proton (H +) to another molecule. A Brønsted-Lowry base is any species that can accept a proton from another molecule. In short, a Brønsted-Lowry acid is a proton donor (PD), while a Brønsted-Lowry base is a proton acceptor (PA).
How many grams are in 8.3 moles of CaCl2?
Answer:
(8.3×40)+(8.3×71)
921.3grames
Answer:
[tex]\Large \boxed{\sf 921.3 \ g}[/tex]
Explanation:
Use formula
[tex]\displaystyle moles=\frac{mass}{M_r}[/tex]
[tex]M_r=40+35.5 \times 2 = 111[/tex]
Solve for mass
[tex]mass=8.3 \times 111=921.3[/tex]
HELP ANYONE THERE
At a research lab, a scientist carelessly pours cultures of living microbes down the drain. Which type of pollution is this?
Question 4 options:
toxic
sediment
nutrient
bacterial
A scientist that carelessly pours cultures of living microbes down the drain represents a type of bacterial pollution.
What is bacterial pollution?Bacterial pollution refers to the uncontrolled proliferation of bacteria in the surrounding environment and ecosystems.
Bacterial pollution can be a subject of concern because bacteria may be pathogenic microorganisms.Bacterial pollution may cause serious harm to the public health and the well-being of a population.In conclusion, a scientist that carelessly pours cultures of living microbes down the drain represents a type of bacterial pollution.
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Prometheus is a character that stole fire from the gods in Greek mythology. Which element is named from Prometheus?
Answer:
Promethium
Pm 61
Discovered by Jacob .A. Marinsky
If you were sitting near a gram of protactinium-234 and a gram of uranium-234, both solid materials, which would you consider more dangerous to you?
aswer: protactinium-234 is more dang erous than uranium
There can be emissions of radiations like gamma radiation. There can be emission of particles too like alpha particle. Therefore protactinium-234 is more dangerous than uranium-234.
What is nuclear decay?Nuclear decay is process in which the radioactive element releases particles or radiations. Alpha particles is ⁴₂He. Alpha particle is nothing but helium particle. Protactinium-234 and uranium-234 are radioactive element.
If we were sitting near a gram of protactinium-234 and a gram of uranium-234, both solid materials then protactinium-234 is more dangerous than uranium-234. The half-life of protactinium-234 is smaller than that of uranium-234. So, protactinium-234 is more active than uranium-234 and hence more harmful than uranium-234.
Therefore, protactinium-234 is more dangerous than uranium-234.
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Which contributes to the polarity of a water molecule?
Oa linear shape along with strong covalent bonds
O deflection of hydrogen atoms by lone pairs of electrons
O no difference in the electronegativity of oxygen and hydrogen
Ohydrogen bond formation between water molecules
Answer:
B
Explanation:
Answer:
B
Explanation:
Edge 2022
what energy is stored
Answer: potential energy is stored
Explanation:
K2S(s) + MgI2 (aq) -----> ?
Answer:
MgS + KI = K2S + MgI2
A 1.250-g sample of benzoic acid, C7H6O2, was placed in a combustion bomb. The bomb was filled with an excess of oxygen at high pressure, sealed, and immersed in a pail of water which served as a calorimeter. The heat capacity of the entire apparatus (bomb, pail, thermometer, and water) was found to be 10.134 kJ/K. The oxidation of the benzoic acid was triggered by passing an electric spark through the sample. After complete combustion, the thermometer immersed in the water registered a temperature 3.256 K greater than before the combustion. What is DEcombustion per mole of benzoic acid burned
Answer:
3224 kJ/mol
Explanation:
The combustion of benzoic acid occurs as follows:
C₇H₆O₂ + 13/2O₂ → 7CO₂ + 3H₂O + dE
The change in temperature in the reaction is the change due the energy released, that is:
3.256K * (10.134kJ / K) = 33.00kJ are released when 1.250g reacts
To find the heat released per mole we have to find the moles of benzoic acid:
Moles benzoic acid -Molar mass: 122.12g/mol-:
1.250g * (1mol / 122.12g) = 0.0102 moles
The dE combustion per mole of benzoic acid is:
33.00kJ / 0.0102moles =
3224 kJ/mol
what are causes of students to drop-out from university
Answer:
stress
Explanation:
people cn get stressed and not want to do work
When 136g of glycine are dissolved in of a certain mystery liquid , the freezing point of the solution is lower than the freezing point of pure . On the other hand, when of sodium chloride are dissolved in the same mass of , the freezing point of the solution is lower than the freezing point of pure . Calculate the van't Hoff factor for sodium chloride in . Be sure your answer has a unit symbol, if necessary, and round your answer to significant digits.
The given question is incomplete. The complete question is:
When 136 g of glycine are dissolved in 950 g of a certain mystery liquid X, the freezing point of the solution is 8.2C lower than the freezing point of pure X. On the other hand, when 136 g of sodium chloride are dissolved in the same mass of X, the freezing point of the solution is 20.0C lower than the freezing point of pure X. Calculate the van't Hoff factor for sodium chloride in X.
Answer: The vant hoff factor for sodium chloride in X is 1.9
Explanation:
Depression in freezing point is given by:
[tex]\Delta T_f=i\times K_f\times m[/tex]
[tex]\Delta T_f=T_f^0-T_f=8.2^0C[/tex] = Depression in freezing point
[tex]K_f[/tex] = freezing point constant
i = vant hoff factor = 1 ( for non electrolyte)
m= molality =[tex]\frac{136g\times 1000}{950g\times 75.07g/mol}=1.9[/tex]
[tex]8.2^0C=1\times K_f\times 1.9[/tex]
[tex]K_f=4.32^0C/m[/tex]
Now Depression in freezing point for sodium chloride is given by:
[tex]\Delta T_f=i\times K_f\times m[/tex]
[tex]\Delta T_f=20.0^0C[/tex] = Depression in freezing point
[tex]K_f[/tex] = freezing point constant
m= molality = [tex]\frac{136g\times 1000}{950g\times 58.5g/mol}=2.45[/tex]
[tex]20.0^0C=i\times 4.32^0C\times 2.45[/tex]
[tex]i=1.9[/tex]
Thus vant hoff factor for sodium chloride in X is 1.9
what are the three components of a chemical formula?
Answer:
The three components of a chemical formula are the empirical formula, the molecular formula, and the structural formula.Hope this answer helps.