Answer:
191.4 grams of cinnabar are required to obtain 165 grams of mercury.
Explanation:
The balanced reaction is:
HgS + O₂ ⇒ Hg + SO₂
By reaction stoichiometry, the following amounts of moles of each compound participate in the reaction:
HgS: 1 mole O₂: 1 mole Hg: 1 mole SO₂: 1 moleBeing the molar mass of each compound:
HgS: 232g/moleO₂: 32 g/moleHg: 200 g/moleSO₂: 64 g/molethe following mass amounts of each compound participate in the reaction:
HgS: 1 mole* 232 g/mole= 232 gO₂: 1 mole* 32 g/mole= 32 gHg: 1 mole* 200 g/mole= 200 gSO₂: 1 mole* 64 g/mole= 64 gThen you can apply the following rule of three: if by stoichiometry 200 grams of Hg are formed from 232 grams of HgS , 165 grams of Hg are formed from how many grams of HgS?
[tex]mass of HgS=\frac{165 grams of Hg*232 grams of HgS}{200 grams of Hg }[/tex]
mass of HgS= 191.4 grams
191.4 grams of cinnabar are required to obtain 165 grams of mercury.
Use a scientific calculator to calculate [H+] for the following pH values:
7 (a neutral solution)
5.6 (unpolluted rainwater)
3.7 (first acid rain sample in North America)
How many times higher is the concentration of H+ in the Hubbard Brook sample than in unpolluted rainwater?
Answer:
pH = 7 ⇒ [H⁺] = 1.0x10⁻⁷ M
pH = 5.6 ⇒ [H⁺] = 2.5x10⁻⁶ M
pH = 3.7 ⇒ [H⁺] = 2.0x10⁻⁴ M
H⁺ concentration in the Hubbard Brook sample is 80 times higher than in unpolluted rainwater.
Explanation:
To answer this problem we need to keep in mind the definition of pH:
pH = -log[H⁺]Meaning that after isolating [H⁺] we're left with:
[H⁺] = [tex]10^{-pH}[/tex]Now we proceed to calculate [H⁺] for the given pHs:
pH = 7 ⇒ [H⁺] = [tex]10^{-7}[/tex] = 1.0x10⁻⁷ MpH = 5.6 ⇒ [H⁺] = [tex]10^{-5.6}[/tex] = 2.5x10⁻⁶ MpH = 3.7 ⇒ [H⁺] = [tex]10^{-3.7}[/tex] = 2.0x10⁻⁴ MFinally we calculate how many times higher is [H⁺] when pH = 3.7 than when pH = 5.6.
2.0x10⁻⁴ / 2.5x10⁻⁶ = 80Answer:
1. 7 (a neutral solution)
Answer: 10-7= 0.0000001 moles per liter
2. 5.6 (unpolluted rainwater)
Answer: 10-5.6 = 0.0000025 moles per liter
3. 3.7 (first acid rain sample in North America)
Answer: 10-3.7 = 0.00020 moles per liter
The concentration of H+ in the Hubbard Brook sample is 0.00020/0.0000025, which is 80 times higher than the H+ concentration in unpolluted rainwater.
Explanation: -
Write the name of flame used In charcoal cavity test.why?
Answer:
the reducing flame also called the carburizing flame.
Explanation:
because it gets the oxides of the unknown salts
what is the function of a prism
Answer:
Prisms are sometimes used for the internal reflection at the surfaces rather than for dispersion. If light inside the prism hits one of the surfaces at a sufficiently steep angle, total internal reflection occurs and all of the light is reflected.
Explanation:
Prism, in optics, piece of glass or other transparent material cut with precise angles and plane faces, useful for analyzing and reflecting light. An ordinary triangular prism can separate white light into its constituent colours, called a spectrum.
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Answer: question 2 is (a) (25+273)k=298k(b) (373+273)k=646k
question 5 is 25 degree Celsius
question 1 is
a = (293-273) =20 degree Celsius
b = (470-273)=197 degree Celsius
question 3 is
a = naphthalene ball undergo sublimation due to which it convert directly into vapour and disappear into air without leaving any solid
b = the participle of perfume diffuse rapidly into air and its smell can be felt while sitting serval metre away
question 4 isthe force of allraction between the particles increases as we go from liquid to gas so the required order is : Oxygen< water< sugar
I hope it is helpful to you
How are the respiratory, urinary, and integumentary systems involved in the removal of waste. (list)
Answer:
The lungs in the respiratory system excrete some waste such as carbon dioxide. The bladder helps to remove waste by urination.HELPP ASAP I’ll mark you as brainlister 100 points :((((
Answer:
the pool table one
Explanation:
cuz gas just goes EVERYWHERE
If you're wearing a yellow shirt in magenta light, what colour does the shirt look like now?
Revise this statement to make it true:
Running water makes rock edges very sharp and pointy.
NEED HELP NOW PLEASE!! WHOEVER ANSWERS FIRST GETS BRAINIEST!!! No links or I’m reporting your answer.
Answer:
Running water makes rock edges very dull because of erosion.
Explanation:
hope this helps ^_^
how far is pluto from jupiter
At which type of tectonic plate boundary is a volcano least likely to occur?
Answer: the answer is a
Explanation:
I took the test and got it wrong because someone said the answer was divergent boundary and it’s wrong. I hate them I hate them I hate them. I hate it I hate school
Transform boundary is the type of tectonic plate boundary is a volcano least likely to occur.
What is meant by Transform boundary?A transform fault or transform boundary, sometimes called a strike-slip boundary, is a fault along a plate boundary where the motion is predominantly horizontal. It ends abruptly where it connects to another plate boundary, either another transform, a spreading ridge, or a subduction zone.Transform boundary is the type of tectonic plate boundary is a volcano least likely to occur.
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What is metal ? Where does it coke from ?
Answer:
Most pure metals, like aluminium, silver and copper, come from the Earth's crust. They are found in ores – solid materials called minerals, usually occurring in rock, from which the pure metal has to be extracted. The properties of pure metals can be improved by mixing them with other metals to make alloys.a metal is an element that readily forms positive ions (cations) and has metallic bonds
coke is a strong stimulant made from coca leaves
Circle all that apply for an anion.
a. Positively charged
b. Negatively charged
c. Metal
d. Nonmetal
e. Loses electrons when formed
f. Gains electrons when formed
g. Listed first in a compound
h. Listed second in a compound
Answer:
b. d. f. h
Explanation:
Anions are negatively charged. They are usually non metals with few exceptions. They need to gain electrons in order to form and they are always listed after cation in a compound.
If you produce 10 g of water in the reaction from 20 g of O2 what is your percent yield? 2H2+O2>2H2O
Answer:
44.4%
Explanation:
The balanced chemical equation for the reaction is:
2 H₂(g) + O₂(g) → 2 H₂O(g)
According to the equation, 1 mol of O₂ produces 2 moles of water (H₂O). We convert the moles to grams by using the molecular weight (Mw) of each compound:
Mw(O₂) = 2 x 16 g/mol O = 32 g/mol
mass O₂ = 1 mol x 32 g/mol = 32 g O₂
Mw(H₂O) = (2 x 1 g/mol H) + 16 g/mol O = 18 g/mol
mass H₂O = 2 mol x 18 g/mol = 36 g H₂O
Thus, from 32 grams of O₂, 36 g of H₂O are produced (stoichiometric ratio= 36 g H₂O/32 g O₂). We calculate the amount of H₂O that would be produced from 20 grams of O₂ by multiplying the stoichiometric ratio by the mass of O₂, as follows:
36 g H₂O/32 g O₂ x 20 g O₂ = 22.5 g H₂O
The theoretical yield of H₂O is 22.5 g, and the actual amount produced is 10 g. So, we calculate the percent yield as follows:
Percent yield = actual yield/ theoretical yield x 100
= (10 g)/(22.5 g) x 100
= 44.4%
What is the volume of an object that has a mass of 5.80 g and a density of 6.35 g/mL?
Answer:
1.09 mL
Explanation:
Density is a measure of a substance's mass over its volume.
d = m/v
We can rearrange the equation to solve for volume, using algebra.
v = d/m
Therefore v = 6.35/5.80 = 1.09 mL
1. What is an air mass? 2. What 2 factors characterize an air mass? 3. What determines the two characteristics of an air mass? 4. What would a cold and wet air mass be called? 5. What would a warm and dry air mass be called? 6. What type of air mass do you think would form over Canada? 7. What kind of weather is associated with a cold front? 8. What kind of weather is associated with a warm front? 9. What symbol on a map represents a warm front? 10. What symbol on a map represents a cold front? 11. What type of weather is associated with a stationary front? 12. How does an occluded front form? 13. What kind of weather can an occluded front bring? 14. What is the symbol on a map to show an occluded front?
Answer:
1. a body of air with horizontally uniform temperature, humidity, and pressure.
2. Boundaries between unlike air masses. Air masses have fairly uniform temperature and moisture content in horizontal direction (but not uniform in vertical). Air masses are characterized by their temperature and humidity properties.
3. Air masses have fairly uniform temperature and moisture content in horizontal direction (but not uniform in vertical). Air masses are characterized by their temperature and humidity properties.
4. Continental air masses are characterized by dry air near the surface while maritime air masses are moist. Polar air masses are characterized by cold air near the surface while tropical air masses are warm or hot.
5. Continental air masses form over land and are dry. Therefore, an air mass that develops over northern Canada is called a continental polar air mass and is cold and dry. One that forms over the Indian Ocean is called a maritime tropical air mass and is warm and humid.
6. an air mass that develops over northern Canada is called a continental polar air mass and is cold and dry.
7. Commonly, when the cold front is passing, winds become gusty; there is a sudden drop in temperature, and heavy rain, sometimes with hail, thunder, and lightning.
8. stormy
9. The symbol that is used to identify a cold front on a weather map is a blue line with triangles that point in the direction in which the cold front is moving. The line is represents the leading edge of the cooler air mass.
10. The symbol that is used to identify a cold front on a weather map is a blue line with triangles that point in the direction in which the cold front is moving. The line is represents the leading edge of the cooler air mass
11. Because a stationary front marks the boundary between two air masses, there are often differences in air temperature and wind on opposite sides of it. The weather is often cloudy along a stationary front, and rain or snow often falls, especially if the front is in an area of low atmospheric pressure.
12. At an occluded front, the cold air mass from the cold front meets the cool air that was ahead of the warm front. The warm air rises as these air masses come together. Occluded fronts usually form around areas of low atmospheric pressure.
13. The temperature drops as the warm air mass is occluded, or “cut off,” from the ground and pushed upward. Such fronts can bring strong winds and heavy precipitation. Occluded fronts usually form around mature low pressure areas.
14.An occluded front is a combination of those two signs. They are indicated on a weather map either by a purple line with alternating semicircles and triangles pointing in direction of travel, or by red semicircles and blue triangles pointing in the same direction.
Explanation:
:)
Answer:
Heya
Explanation:
1) air mass:- An air mass is a large volume of air in the atmosphere that is mostly uniform in temperature and moisture.
2) Air masses are characterized by their temperature and humidity properties.
3) ( same answer i.e. temperature and humidity properties).
4) Colder air masses are termed polar or arctic, while warmer air masses are deemed tropical. Continental and superior air masses are dry while maritime and monsoon air masses are moist. Weather fronts separate air masses with different density (temperature or moisture) characteristics.
5) Continental air masses are characterized by dry air near the surface while maritime air masses are moist. Polar air masses are characterized by cold air near the surface while tropical air masses are warm or hot. Arctic air masses are extremely cold.
6) Maritime air masses form over water and are humid. Continental air masses form over land and are dry. Therefore, an air mass that develops over northern Canada is called a continental polar air mass and is cold and dry.
7) Commonly, when the cold front is passing, winds become gusty; there is a sudden drop in temperature, and heavy rain, sometimes with hail, thunder, and lightning. Lifted warm air ahead of the front produces cumulus or cumulonimbus clouds and thunderstorms.
8) Warm fronts often bring stormy weather as the warm air mass at the surface rises above the cool air mass, making clouds and storms. Warm fronts move more slowly than cold fronts because it is more difficult for the warm air to push the cold, dense air across the Earth's surface.
9) The symbol that is used to identify a warm front on a weather map is a red line with half circles that point in the direction in which the warm front is moving. The line represents the leading edge of the warmer air mass.
10) On weather maps, the surface position of the cold front is marked with the symbol of a blue line of triangles/spikes (pips) pointing in the direction of travel.
11) Because a stationary front marks the boundary between two air masses, there are often differences in air temperature and wind on opposite sides of it. The weather is often cloudy along a stationary front, and rain or snow often falls, especially if the front is in an area of low atmospheric pressure.
12)At an occluded front, the cold air mass from the cold front meets the cool air that was ahead of the warm front. The warm air rises as these air masses come together. Occluded fronts usually form around areas of low atmospheric pressure.
13) The warm air mass rises as the cool air masses push and meet in the middle. The temperature drops as the warm air mass is occluded, or “cut off,” from the ground and pushed upward. Such fronts can bring strong winds and heavy precipitation. Occluded fronts usually form around mature low pressure areas.
14)Occluded fronts are drawn as a solid purple line with half circles and triangles pointing in the direction that the front is moving. An occluded front usually brings dry air.
[tex] \underline \blue{ \fbox{check \: the \: attachment \: too \: :) }}[/tex]
How many moles of CO2 are produced from 16 grams of O2
Answer:
One mole of CO2 has mass of 44 g and 32 g of O2. So 16 g of O2 have 22 g of CO2 or 0.5 moles of it.
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Explanation:
Which of the following describes experiences initiated spontaneously by children as they go about their daily activities?
Naturalistic experiences
Informal learning experiences
Structured learning experiences
Disorganized experiences
Answer:
naturalistic
Explanation:
Using the diagram , what is the intersection of plan ABCD and GC?
Answer:
C
Explanation:
When a line segment and a plane intersect, they intersect at a point. They both coincide on point C
The value of Kp for the reaction 2 A(g) + B(g) + 3 C(g) → 2 D(g) + E(g) is 18530 at a particular temperature. What would be the value of Kp for the reaction 2 D(g) + E(g) → 2 A(g) + B(g) + 3 C(g)?
Answer:
[tex]Kp2=5.3967x10^{-5}[/tex]
Explanation:
Hello there!
In this case, since the Kp for the first reaction is given, according to the following equilibrium expression:
[tex]Kp=\frac{p_D^2p_E}{p_A^2p_Bp_C^3} =18530[/tex]
However, since the second reaction stands for the reverse of the initial one, the equilibrium expression would be:
[tex]Kp_2=Kp=\frac{p_A^2p_Bp_C^3}{p_D^2p_E}[/tex]
And therefore its Kp the inverse of the aforementioned one:
[tex]Kp2=1/18530\\\\Kp2=5.3967x10^{-5}[/tex]
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how many moles is 130g of cocl2
Answer:
1.3142 mol CoCl2
Explanation:
Well, to answer this we need to find out how many grams are in a single mole of CoCl2. Two find that we need to get the molar mass of CoCl2
Co = 28.0101 g Co per mole
Cl = 35.453 * g Cl per mole
28.0101 + 2 * 35.453 = 98.9161 g CoCl2 per mole
Now, we divide:
130/98.9161 = 1.3142 mol CoCl2
There are 1.31 moles in 130grams of cobalt chloride (CoCl2). Details about how to convert mass to moles can be found below.
How to calculate number of moles?The number of moles of a substance can be calculated by dividing the mass of the substance by its molar mass.
According to this question, there are 130g of CoCl2.
molar mass of CoCl2 = 28 + 35.5(2) = 99g/mol
moles = 130g ÷ 99g/mol
moles = 1.31 moles
Therefore, there are 1.31 moles in 130grams of cobalt chloride (CoCl2).
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If you have 12 atoms of hydrogen before a chemical reaction, how many atoms of hydrogen will be present
Answer:
12 atoms of hydrogen will be present in the product
Explanation:
12 atoms of hydrogen will be present in the product because the law of conservation of mass states that mass is neither created nor destroyed in chemical reactions.
The law of conservation states that the mass of the element remains the same during the course of the reaction.
The law of reaction conformed by the following:-
Mass of reactant Mass of productAccording to the question, the amount of hydrogen is 12 atoms in the reactant and the amount will remain the same at the end of the reaction, which is a product that is 12 atoms
Hence, the amount remains the same in the reaction that is 12 atoms
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Which equation is correctly balanced?
A) CaO + 2H2O + Ca(OH)2
B) NH3 + 202 → HNO3 + H20
C) Ca(OH)2 + 2H3PO4 → Ca3(PO4)2 + 3H2O
D) Cu + H2SO4 → CuSO4 + H2O + SO2
CaO + 2H2O + Ca(OH)2 is a balance chemical equation. Therefore, option A is correct.
What is balance chemical equation ?A balanced chemical equation is one that has the same number of atoms of each type in the reaction on both the reactant and product sides. In a balanced chemical equation, both the mass and the change are equal.
When a chemical reaction occurs, the mass of the products should be equal to the mass of the reactants, according to the law of conservation of mass. As a result, the number of atoms in each element remains constant during the chemical reaction. As a result, the chemical equation must be corrected.
The chemical equation is said to be balanced if there are no inequalities. Every element in this example now has an equal number of atoms on both the reactant and product sides.
Thus, option A is correct.
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160
140
120
100
Temperature (°C)
80
60
40
20
0
0
2 4 6 8
10 12 14 16 18 20 22 24 26
Time (min)
.
At what temp will this substance freeze? 70 CV
At what temp will this substance condense? 70 C
How long will it take to release the heat of vaporization? 3 min
What is the melting point? 70 C
In what physical state did this substance end? Gas
All cooling processes, including phase changes, are Exothermic
At 90 C, what phase of matter is this substance? Liquid
A 25.00 mL sample of the ammonia solution
was accurately diluted to 250.0 mL. A 25.00mL
aliquot of the diluted ammonia solution was
placed in a conical flask. Indicator was then added
and the solution was titrated with 0.208 molL-1
hydrochloric acid. The indicator changed colour
permanently when 19.64 mL of the acid had been
added. Calculate the concentration of ammonia in
the original solution.
Answer:
1.634 molL-1
Explanation:
The mol ration between NH3 and HCl is 1 : 1
Using Ca Va / Cb Vb = Na / Nb where a = acid and b = base
Na = 1
Nb = 1
Ca = 0.208 molL-1
Cb = ?
Va = 19.64 mL
Vb = 25.00mL
Solving for Cb
Cb = Ca Va / Vb
Cb = 0.208 * 19.64 / 25.0
Cb = 0.1634 molL-1 (Concentration of diluted ammonia solution)
Using the dilution equation;
C1V1 = C2V2
Initial Concentration, C1 = ?
Initial Volume, V1 = 25.00 mL
Final Volume, V2 = 250 mL
Final Concentration, C2 = 0.1634 molL-1
Solving for C1;
C1 = C2 * V2 / V1
C1 = 0.1634 * 250 / 25.00
C1 = 1.634 molL-1
potassium hydroxide , sodium chloride, sodium hydroxide ,calcium chloride , sodium bicarbonate write molecular formula
✧ [tex] \underline{ \underline{ \large{ \tt{A \: N \:S \: W \: E \: R}}}} : [/tex]
[tex] \underline{ \underline{ \large{ \text{Molecular \: Formulaes}}}} : [/tex]
⇾ [tex] \large{ \text{Potassium \: Hydroxide : K \: OH}}[/tex]
⇾ [tex] \large{ \text{Sodium \: Chloride : NaCl}}[/tex]
⇾ [tex] \large{ \text{Sodium \: Hydroxide : NaOH}}[/tex]
⇾ [tex] \large{ \text{Calcium \: Chloride : CaCl}}[/tex]
⇾ [tex] \large{ \text{Sodium \: Bicarbonate} : \tt{Na ( HCO)_{ 3} }}[/tex]
---------------------------------------------------------
☥ [tex] \underline{ \underline{ \large{ \tt{ \: E \: X\: P \: L\: A\: N \: A \: T \: I \: O \: N}}} }: [/tex]
[tex] \underline{ \underline{ \text{Writing \: a \: molecular \: formula}}} : [/tex]
To write a molecular formula , the following steps are usually adopted only when we know the symbol and valencies of elements and radicals present in a molecule.
Step 1 : First , the name of the compound is written.
Step 2 : The symbols of basic and acidic radicals are written side by side.
Step 3 : The valency of each radical is written at the right upper corner of the symbol. The valency of one radical is transferred to another radical and it is written on the right hand side at the bottom corner. If necessary , L.C.M of the valencies us taken to get a simple whole number.
Step 4 : If a compound radical takes part in the molecular formula , the radical is enclosed in brackets and the valency number is written on the right side of the bracket at the bottom of the formula.
For instance :
[tex] \text{Calcium \: \: \: \: \: \: Sulphate}[/tex] [ compound ]
1. [tex] \sf{Ca \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: SO_{4} }[/tex] [ Symbol of basic and acidic radicals ]
2.We know : Valencies of calcium and sulphate are 2 and 2 respectively
3. [tex] \sf{Ca_{2} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: (SO_{4} )_{2} }[/tex] [ Valencies are exchanged and compound radical is enclosed in bracket ]
4.[tex] \sf{CaSO_{4}}[/tex] [ L.C.M is taken to get molecular formula of calcium sulphate ]
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What makes water unique?
In your response be sure to include:
properties of water
dont use go0gle nor guess plz this is due at midnight
Answer:
Water is unique because of our need to survive on something so simple. It is just 2 hydrogen atoms and an oxygen. so simple, but necessary for all of our lives. Just 3-4 minutes without it causes permanent damage
What ratio of NaCN to HCN is needed to prepare a pH 9.40 buffer? (Ka of HCN is 4.9 × 10⁻¹⁰)
Answer: The ratio of NaCN to HCN is, 1.26
When dissolved in water all acids will???
Answer:
When dissolved in water, acids donate hydrogen ions (H+). Hydrogen ions are hydrogen atoms that have lost an electron and now have just a proton, giving them a positive electrical charge. Bases, on the other hand, mixed with water yield hydroxide ions (OH-). If a solution has a high concentration of H+ ions, then it is acidic.
Explanation:
So b
when a rotting log was turned over, pill bugs, termites , ants , fungi , and earthworms were living there. the termites represent ____ in its
a. an environment
b. a population
c. a niche
d. an abiotic factor
Did anyone do this worksheet (science)