1) If you had 500 H2 molecules and 1000 O2 molecules, how many water molecules could you produce?

2) If you had 500 H2 molecules , how many O2 molecules would you need to completely react all of the H2 prime?

3) Do not solve the following problem, but explain how it could be answered. 500 g of H2 and 1000 g of O2 are placed in a reaction vessel. How many grams of water could be produced ?

two moles of hydrogen gas produces 2 moles of water. Then 500 molecules of hydrogen will produce 500 molecules of water. Similarly, 500 molecules of hydrogen gas needs 250 molecules of oxygen gas to react.

Any substance containing 6.02 × 10²³ atoms is called one mole of the substance. This number is called Avogadro number.

The reaction of hydrogen and oxygen giving water can be written as :

[tex]\rm 2H_{2} + O_{2} \rightarrow 2 H_{2}O[/tex]

As per this reaction, two moles of hydrogen gives two moles of water. 2 moles of each contains 2 × 6.02 × 10²³ molecules.

Thus, 500 molecules of hydrogen gives 500 molecules of water.

2 × 6.02 × 10²³ molecules of hydrogen needs 6.02 × 10²³ molecules of oxygen, Then, 500 molecules of hydrogen needs 250 oxygen molecules.

Similarly, 2 moles or 4 g of hydrogen produces 2 moles or 36 g of water. Then 500 g of hydrogen will produce 4500 g of water.

Find more on Avogadro number:

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