1. If a 4000 kg rocket reaches 7,000 m/s in 8 minutes after blastoff, what is its acceleration?

2. What force is being applied to the rocket?

3. What is the rocket's potential energy when it is 12 km off the ground?
(Hint - Change kilometers to meters)

4. If the rocket were to fall from the 12 km height, what would be its speed right before hitting the ground? (assume no air resistance)

+ answer all the questions plz

Answers

Answer 1

Answer:

I guess the Ans for second one is gravitational force

Related Questions

When 26400j of energy is supplied to a 2.0kg bloom of aluminum it temperature rise from 20oc to 35oc.The block is well so there is no energy lost to sorround determine the specific heat capacity of aluminum

Answers

Answer:

880J/kelvin

Explanation:

Q =MC ×change in t

c =C/m

C=Q/change in t

c= Q/ m× change in t

c = 26400 / 2.0 × 15

c = 880 J/kelvin

Define a rotation of the earth answer fast

Answers

Answer:

here u go

Explanation:

Earth's rotation is the rotation of planet Earth around its own axis. Earth rotates eastward, in prograde motion. As viewed from the north pole star Polaris, Earth turns counterclockwise.

A ball of mass 4kg moving with a velocity of 20m/s collides with another ball of mass 15kg moving with a velocity of 15m/s in the same direction. Calculate the velocity of the 5kg ball if the collision is perfectly inelastic.

Answers

Answer:

velocity = 16.05 m/s

Explanation:

inelastic collision formula:

m1u1 + m2u2 = (m1 + m2)v

m1 = 4kg

u1 = 20m/s

m2 = 15kg

u2 = 15m/s

find v ?

m1u1 + m2u2 = (m1 + m2)v

(4×20) + (15×15) = (4+15)v

80 + 225 = 19v

305 = 19v

19v = 305

v = 305/19

v = 16.05 m/s

Use the following free body diagram to answer questions 8 and 9:

8. Calculate the net force acting on the cart.
A 0N
B. +60N
C -60N
D. +240 N
9. Calculate the cart's rate of acceleration
A +60 m/s
B. +8 m/s
C.-2m/s
D. +2 m/s

Answers

Answer:

8 is c and 9 is b it is shown though the practice as god lol

Question 8

The net force acting on the cart is:

F = 150 N - 90 N

F = 60 N

Question 9

By the Newtons second law:

F = ma

Solving for a:

a = F/m

a = 60 N / 30 kg

a = 2 m/s²

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