1) Construct a graph showing the relationship between and independent variable and a dependent variable. 2) Demonstrate potential and kinetic energy. 3) Design a pendulum. 4) Investigate which variables influence the period of a pendulum. 5) Solve a problem using the scientific method. 6) Use graphs to characterize gow drop height responds to bounce height. (Next answer questions 1 - 6). 1) Write the goal of the lab or the question you tried to answer? 2) which observations, experiences, or lesson materials helped you form a hypothesis? 3) State your hypothesis? 4) Use the data from your experiment to complete these data tables? [Data Table 1: Period vs. Mass] Mass(g) / Time for 10 periods (s). [ Data Table 2: Period vs. String Length] String Length (cm) / Time for 10 periods (s). ( Question 5) Graph your data: A) Determine the values in seconds (s) for the y-axis based on your time data. B) Plot mass vs. time for 10 periods on the first graph. C) Plot string length vs. time for 10 periods on the second graph. ( question 6) Compare your data with your hypothesis. Explain how the data supports or does not support your hypothesis. If your data does not support your hypothesis, use the data you collected to answer the original question. { Truly Need Help and will mark brainlest} Please Please be very honest with your response. ​

Answer:

The magnetic field at the center of a circular current loop of radius R divided by the magnetic field at a distance R away from a very long straight wire carrying the same current value I is [tex]\pi[/tex] or 3.14

Explanation:

The magnetic field at center of a circular loop is given by

[tex]B = \frac{\mu _{o}I }{2R}[/tex]

Where B is the magnetic field

[tex]\mu _{o}[/tex] is the free space permeability constant ( [tex]\mu _{o}[/tex] = 4π × 10⁻⁷ N/A²)

[tex]I[/tex] is the current

and [tex]R[/tex] is the radius

For the magnetic field of a long straight wire, it is given by

[tex]B = \frac{\mu _{o}I }{2\pi R}[/tex]

Where B is the magnetic field

[tex]\mu _{o}[/tex] is the free space permeability constant ( [tex]\mu _{o}[/tex] = 4π × 10⁻⁷ N/A²)

[tex]I[/tex] is the current

and [tex]R[/tex] is the distance from the wire

Then, to calculate the magnetic field at the center of a circular current loop of radius R divided by the magnetic field at a distance R away from a very long straight wire carrying the same current value I, that will be

[tex]\frac{\mu _{o}I }{2R} \div \frac{\mu _{o}I }{2\pi R}[/tex]

= [tex]\frac{\mu _{o}I }{2R} \times \frac{2\pi R }{\mu _{o}I}[/tex]

= [tex]\pi[/tex]

(NOTE: [tex]\pi[/tex] = 3.14)

Hence, the magnetic field at the center of a circular current loop of radius R divided by the magnetic field at a distance R away from a very long straight wire carrying the same current value I is [tex]\pi[/tex] or 3.14.

Answer: The motion of a ball falling down through the atmosphere, or a model rocket being launched up into the atmosphere are both examples of Newton's first law. The motion of a kite when the wind changes can also be described by the first law.

Explanation:

Answer:

A

Explanation:

Switches are used to block electrical currents, thus needing to be made out of insulating material.

Complete Question

A 6.00-µc charge is moving with a speed of 7.50x10^4 m/s parallel to a very long, straight wire. the wire is 5.20 cm from the charge and carries a current of 68.5 A in a direction opposite to that of the moving charge. Calculate the magnitude of the force on the charge.

Answer:

The value is [tex]F =1.20 *10^{-4} \ N[/tex]

Explanation:

From the question we are told that

     The magnitude of the charge is  [tex]Q = 6.00\muC = 6.00 *10^{-6} \ C[/tex]

      The speed is  [tex]v = 7.50 *10^{4} \ m/s[/tex]

      The distance of the wire from the charge is  [tex]d = 5.20 \ cm = 0.0520 \ m[/tex]

       The current flowing through the wire in the opposite direction to the charge  is  [tex]I _2 = 68.5 \ A[/tex]

  Gnerally the magnitude of force on that charge is mathematically represented as

      [tex]F = qvB[/tex]

Here B is magnetic field which is mathematically represented as

              [tex]B = \frac{\mu_o * I}{2\pi d}[/tex]

Here  [tex]\mu_o[/tex] is the permeability of free space with value  [tex]\mu_o = 4\pi * 10^{-7} N/A^2[/tex]

 So

       [tex]F = qv[\frac{\mu_o * I}{2\pi d}][/tex]

=>     [tex]F = 6.0*10^{-6} * (7.50 *10^{4})[\frac{4\pi * 10^{-7} * 68.5 }{2* 3.142 * 0.0520 }][/tex]      

=>    [tex]F =1.20 *10^{-4} \ N[/tex]

Answer:

Hans Christian Oersted

Explanation:

Answer:

26 m/s

Explanation:

v = u + at

Given that,

and v ( final velocity) = ?

v = 18 + ( 4 × 2)

v = 18 + 8

v = 26 m/s

Answer:

[tex]3. \: From \: 6 \: to \: 8 \: seconds, \: Elan \: \\ accelerated \: \: faster \: than \: Anna. [/tex]

Answer:

What are the choices?

Explanation:

Answer:

20.14 KG

Explanation:

apex keepy o heads up stay positive don't stress over something useless big future 4 all of yall!

The mass is 20.14 kg

Answer:

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

[tex]volume = \frac{mass}{density} \\[/tex]

From the question

mass = 35 g

volume = 5 g/cm³

We have

[tex]volume = \frac{35}{5} \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

about 42.35 m/s

Explanation:

Use the equation for accelerated motion (g), and with zero initial velocity that doesn't include time:

[tex]v_f^2=v_i^2+2\,a\,\Delta x[/tex]

which for our case would reduce to:

[tex]v_f^2=v_i^2+2\,a\,\Delta x\\v_f^2=0+2\,9.8\,(91.5)\\v_f^2= 1793.4\\v_f=\sqrt{1793.4} \\v_f \approx 42.35[/tex]

then the velocity just before hitting would be about 42.35 m/s

Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

[tex]a = \frac{f}{m} \\ [/tex]

where

m is the mass

f is the force

We have

[tex]a = \frac{275}{18} \\ = 15.277777...[/tex]

We have the final answer as

Hope this helps you

Answer:  If you are performing an experiment on the effect of spraying plants with different chemicals, you would try to maintain the same pressure and maybe the same volume when spraying your plants. The independent variable is the one factor that you are changing. It is one factor because usually in an experiment you try to change one thing at a time.

Explanation:

Answer: a constant? im not sure that just sounds like itd be right.

Explanation:

Answer:

b

Explanation:

because he isn't moving

Answer:

when it weighs 2kg it is 7.38

Explanation:

hope this helps

Answer:

Centripetal acceleration must involve a change in a. an object's tangential speed.

Explanation:

Centripetal acceleration must involve a change in direction of motion of the object.

centripetal acceleration is the acceleration of a body traversing a circular path. Because velocity is a vector quantity (that is, it has both a magnitude, the speed, and a direction), when a body travels on a circular path, its direction constantly changes and thus its velocity changes, producing an acceleration. The acceleration is directed radially toward the center of the circle.

In your daily existence, you must have encountered numerous instances of centripetal acceleration. A centripetal acceleration occurs when you drive in a circle, and a centripetal acceleration also occurs when a satellite orbits the earth. Centripetal refers to being in the center.

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Answer:

3/4 0r 0.75

Explanation:

Let E represent the extra cash.

Let R represent the amount raised.

From the question given above, we can say that:

The extra cash (E) is directly proportional to the amount raised (R) i.e

Extra cash (E) ∝ Amount raised (R)

E ∝ R

E = KR

NOTE: K is the constant of proportionality.

With the above formula, we can obtain the value of K as follow:

Extra cash (E) = $ 75

Amount raised (R) = $ 100

Constant of proportionality (K) =?

E = KR

75 = K × 100

Divide both side by 100

K = 75/100

K = 3/4 0r 0.75

Thus, the constant of proportionality is 3/4 0r 0.75

Answer:

124m/s

Explanation:

v=u+at

v=119+(0.5×10)

v=119+5

v=124m/s

Answer:

Newton 3 laws

Explanation:

1.object will not change its motion unless a force acts on it . 2.the force on an object is equal to it's time mass on acceleration. 3. When 2 o jecys interact they apply forces to each other of equal.

Answer:

Soils develop faster in warm, moist climates and slowest in cold or arid ones. Rainfall is one of the most important climate factors in soil formation.

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Hope this helped God bless :)

Soil formation occurs more swiftly in warm, humid areas than it does in cold or arid ones.One of the most crucial climatic variables for the formation of soil is rainfall. The breakdown of large soil particles into smaller ones is accelerated by creatures such as bacteria, plants, and animals.

The rate of chemical reactions is accelerated by rising temperature, which also accelerates soil formation. Faster plant and bacterial growth in warmer climates aids in the weathering of materials and the formation of soils.

The formation of soil is another indirect effect of climate on organisms. Weathering is accelerated by precipitation and warm temperatures, which increases the amount of soil development. Rainfall increases the amount of organic matter, lowers pH, accelerates the leaching of basic ions, moves mud, etc.

Therefore, In warm, wet regions, soil development happens more quickly than in cold or arid ones. One of the most crucial climatic variables for the formation of soil is rainfall.

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Answer:

y=0.5 g t^2

=0.5*10*2^2

=20 m

9514 1404 393

Answer:

  0.2 m/s

Explanation:

The average velocity is the change in position divided by the change in time:

  (8 m -4 m)/(20 s) = (4/20) m/s = 1/5 m/s = 0.2 m/s

The boy's average velocity is 0.2 m/s.

Answer:

V = 0.07525 [m³]

U  = 655.74 [kJ]

Explanation:

To solve this problem we must use the superheated refrigerant table for refrigerant 134a. The attached image shows the specific volume and specific internal energy values for a pressure of 800 [kPa] and a temperature of 120 [°C].

m = mass =2 [kg]

the specific volume = v = 0.037625 [m³/kg]

The volume of the tank can be found using the following expression:

V = v*m

V = 0.037625*2 = 0.07525 [m³]

The Specific internal energy = u = 327.87 [kJ/kg]

U = u*m

U = 327.87*2 = 655.74 [kJ]

Answer:

Normal force = 751.75 N

Explanation:

It is given that,

The combined weight of the cyclist and the bike is 800 N

We need to find the magnitude of the normal force of the ground on the bike. It can be given by the formula as follows :

[tex]N=mg\cos\theta[/tex]

mg = W, combined weight of cyclist and bike

[tex]N=W\cos\theta\\\\N=800\times \cos(20)\\\\N=751.75\ N[/tex]

So, the magnitude of the normal force of the ground on the bike is 751.75 N.

The magnitude of the normal force of the ground on the bike is 751.752 N

The formula for that will be used to calculate the normal force of the ground on the bike is expressed as:

[tex]N= Fcos \theta[/tex]

F is the combined weight

[tex]\theta[/tex] is the angle of inclination

Given the following paramters

F = 800 N

[tex]\theta[/tex] = 20 degrees

Substitute the given parameters into the formula:

[tex]N=800 \times cos20^0\\N=800 \times 0.9397\\N=751.752N[/tex]

Hence the magnitude of the normal force of the ground on the bike is 751.752 N

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Answer:

4 s

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 19.4 m/s.

Acceleration due to gravity (g) = –9.81 m/s²

Total time (T) =.?

Next, we shall determine the time take by the rock to get to the maximum height. This can be obtained as follow:

NOTE: At maximum height, the final velocity is zero.

Initial velocity (u) = 19.4 m/s.

Acceleration due to gravity (g) = –9.81 m/s²

Final velocity (v) = 0 m/s

Time taken to reach the maximum height (t) =.?

v = u + gt

0 = 19.4 + (–9.81 × t)

0 = 19.4 – 9.81t

Collect like terms

0 – 19.4 = –9.81t

–19.4 = –9.81t

Divide both side by –9.81

t = –19.4 / –9.81

t ≈ 2 s

Thus, it took approximately 2 s for the rock to reach its maximum height.

Finally, we shall determine the total time spent by the rock in the air as follow:

Time taken to reach the maximum height (t) = 2 s

Total time spent in air (T) =?

The total time (T) spent by the rock in the air will be two times the time taken (t) to reach the maximum height i.e

T = 2t

t = 2 s

T = 2 × 2

T = 4 s

Therefore, the rock spent approximately 4 s in the air.

Well first you need to know the formula for the spring force. It’s -1/2k*d

K being the constant

D being the displacement

We can actually find the force on the spring by calculating the weight of the block. It would be mass multiplied by gravity, convert the grams to kilograms first tho.

600/1000 = 0.6kg

0.6kg * 9.8 m/s^2 = 5.88N

Now plug everything into the equation, also convert the centimeters to meters:

1.2/100 = 0.012 meters

5.88 = -1/2k*(0.012)

5.88 = k*(0.006)

We could drop the negative sign because we really just want the magnitude of the spring constant.

K = 980N

Answer:

bc of their paw pads, they don't get the traction they need in order to be able to get a firm grip to push off of on the table for each bound

Explanation:

Answer:

a

[tex]The  \ price \  for \   Compact\ fluorescent\ bulbs \ is  \ C_T  = \$ 21.067\\The   \ price \  for \    incandescent\ bulb \ is \ C_t  = \$ 43.98[/tex]

b

[tex]The \  amount  \  saved \ is  \ C_S =  \$ 22.913[/tex]

c

[tex]The \ resistance \  is \ R =  626.1 \Omega[/tex]

Explanation:

From the question we are told that

   The power used by incandescent bulb [tex]P_r  =  23.0 W[/tex]

    The power used by  Compact fluorescent bulb [tex]P_p  =  100W[/tex]

     The life span of  Compact fluorescent bulb is  [tex]t = 1000 \  hours[/tex]

    The  prices of   Compact fluorescent bulb is [tex]C_c = \$ 12 [/tex]

    The  prices of incandescent bulb is [tex]C_i = \$ 0.76 [/tex]

     The life span of   incandescent bulb is  [tex]t_k = 750   \ hours[/tex]

      The cost of electricity is [tex]C_e =  \$ 0.090/ kilowatt-hour = \frac{0.090}{1000} = \$0.00009 / W / h[/tex]

    The duration of daily bulb usage is [tex]t_d  =  4 \  hours[/tex]

Generally 3 years of bulb usage  in hours is mathematically evaluated as

    [tex]t_3 =  3 *  365 *  t_d[/tex]

=>   [tex]t_3 =  3 *  365 *  4[/tex]

=>   [tex]t_3 =  4380 \ h [/tex]

Generally the cost to power a 23W bulb for the above duration  is mathematically represented as

 [tex]Z = 23 *  t_3 * C_e[/tex]

=>   [tex]Z = 23 *  4380 * 0.00009[/tex]

=>   [tex]Z = \$ 9.0667[/tex]

The number of Compact fluorescent bulbs required to  achieve this about of time is mathematically represented as

       [tex]N  =  \frac{t_3}{ t}[/tex]

=>  [tex]N  =  \frac{4380}{1000}[/tex]

=>   [tex]N  = 0.438 [/tex]

=>  [tex]N  \approx  1 [/tex]

The total cost of  usage  for the Compact fluorescent bulb   is  mathematically represented as

      [tex]C_T  =  Z +C_c[/tex]

=>   [tex]C_T  =  9.0667 +12[/tex]

=>   [tex]C_T  = \$ 21.067 [/tex]    

The number of  incandescent bulbs required to  achieve this about of time is mathematically represented as

       [tex]M =  \frac{t_3}{ t_k}[/tex]

=>  [tex]M  =  \frac{4380}{750}[/tex]

=>   [tex]M  = 6 [/tex]

Generally the cost to power a 100W bulb for the above duration  is mathematically represented as

 [tex]Z = 100 *  t_3 * C_e[/tex]

=>   [tex]Z = 100 *  4380 * 0.00009[/tex]

=>   [tex]Z = \$ 39.42[/tex]

The total cost of  usage  for the incandescent bulbs    is  mathematically represented as

      [tex]C_t  =  C_e + [6 *C_i][/tex]

=>   [tex]C_t  =  39.42 + [0.76 *  6][/tex]

=>   [tex]C_t  = \$ 43.98[/tex]    

Generally the total amount saved is mathematically represented as

   [tex]C_S =  C_t - C_T[/tex]

=>   [tex]C_S =  43.98 - 21.067[/tex]

=>   [tex]C_S =  \$ 22.913[/tex]

Generally the resistance of the Compact fluorescent bulb is  

    [tex]R =  \frac{V^2}{P}[/tex]

    [tex]R  =  \frac{120^2}{23}[/tex]

[tex]R =  626.1 \Omega[/tex]