1 bag of takis cost 2.25 dollars and 1 soda cost 1.50 dollars. if he buy 16 total items and spend 30.75 dollars,how many bags of takis did he buy and how many sodas did he bug

The statement that describes the graph of y-√√-4x-36 compared to the parent square root function is: d. stretched by a factor of 2, reflected over the y-axis, and translated 9 units left

Stretch by a factor of 2: Multiply the input of the function by 2. The new function is f(2x).

Reflect over the y-axis: Negate the output of the function. The new function is -f(2x).

Translate 9 units left: Subtract 9 from the input of the function. The new function is -f(2x - 9). So if you have an original function f(x) the transformed function would be -f(2x - 9).

Therefore the correct option is d.

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Answer:

x= 129°

Step-by-step explanation:

Angle x is suplenment of 51° (their sum = 180°)

So x+51° = 180°

x = 180° - 51°

x= 129°

Based on the sample, we can estimate that about 181 Grade 8 students in the school plan to take computer science in high school.

We have,

To estimate the number of Grade 8 students in the school who plan to take computer science in high school, we can use the proportion of students in the sample who plan to take computer science.

The proportion of students who plan to take computer science in the sample.

= 15/27

= 0.5556

We can assume that this proportion is representative of the entire Grade 8 population in the school.

To estimate the number of Grade 8 students who plan to take computer science, we can multiply this proportion by the total number of Grade 8 students in the school:

= 0.5556 x 326

= 181

Therefore,

Based on the sample, we can estimate that about 181 Grade 8 students in the school plan to take computer science in high school.

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Here is the completed two-column proof:

Given: ZA and B are complementary angles. ZB and ZC are complementary angles.

Reasons Statements

Given ZA + B = 90° and ZB + ZC = 90°

Definition of complementary angles |

ZA = 90° - B and ZB = 90° - ZC

Substitution property of equality |

90° - B = 90° - ZC

Subtraction property of equality |

ZA = ZC

Angles that have equal measure are congruent |

ZAZC

Complementary angles are a pair of angles that add up to 90 degrees. In other words, when you have two complementary angles, the sum of their measures is always 90 degrees. Each angle in a pair of complementary angles is said to be the complement of the other angle.

For example, if you have one angle that measures 30 degrees, its complement would measure 60 degrees, because 30 + 60 = 90. Similarly, if you have an angle measuring 45 degrees, its complement would be 45 degrees as well, because 45 + 45 = 90.

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The marginal revenue (MR) curve for a monopoly firm is given by the derivative of the total revenue (TR) curve with respect to quantity (Q).

Total revenue (TR) is the product of price (P) and quantity (Q), i.e., TR = P × Q.

Differentiating TR with respect to Q, we get:

MR = dTR/dQ = d(P×Q)/dQ = P + Q×dP/dQ

The inverse demand curve given is: P = 400 - 8Q

Taking the derivative of P with respect to Q, we get:

dP/dQ = -8

Substituting this value into the above equation for MR, we get:

MR = 400 - 8Q + Q×(-8) = 400 - 16Q

Therefore, the correct answer is option (a) MR = 400 - 16Q.

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Answer:

k is the hypotenuse,

l is the opposite

j is the adjacent

Step-by-step explanation:

assuming L is theta

The critical angle between these two materials does not exist.

The critical angle θc is given by the equation sin θc = nB/na, where na and nB are the refractive indices of the two materials. Substituting na = 1.65 and nB = 2.12 into this equation, we get sin θc = 2.12/1.65 = 1.2848. However, since the sine function is only defined between -1 and 1, this means there is no real value of θc that satisfies this equation. Therefore, the critical angle between these two materials does not exist.

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Answer:

x = 3, y = -2

Step-by-step explanation:

Substitute Y = -2 into the second equation:

4x - 3(-2) = 18

Simplify and solve for x:

4x + 6 = 18

4x = 12

x = 3

Now substitute x=3 into the first equation to solve for y:

Y = -2

Therefore, the solution to the system of equations is:

x = 3, y = -2

Answer:

Set your calculator to degree mode.

tan(67°) = h/50

h = 50tan(67°) = 118 meters

Answer: 5

Step-by-step explanation: pythag

We need to find an inner function u=g(x) and an outer function y=f(u) such that y=f(g(x)), and then find dy/dx in terms of du/dx.

Let u = g(x) = a + x, where a is a constant. Then y = f(u) = f(a + x).

If y = f(a + x), then we can express y in terms of u as y = f(u) = f(g(x)) = f(a + x).

Using the chain rule, we have:

dy/dx = dy/du * du/dx

We can find dy/du by taking the derivative of f(u) with respect to u:

dy/du = f'(u)

And we can find du/dx by taking the derivative of g(x) with respect to x:

du/dx = 1

Therefore, we have:

dy/dx = dy/du * du/dx = f'(u) * 1

So the correct answer is: dy/du.

For the second question:

We have y = 7(7x^3 + 8)^-6.

Using the power rule and the chain rule, we have:

dy/dx = -6 * 7 * (7x^3 + 8)^-7 * d/dx(7x^3 + 8)
= -294 * (7x^3 + 8)^-7 * 21x^2

So the correct answer is: -294(7x^3 + 8)^-7 * 21x^2.

For the third question:

We have y = sec(2x - 1).

Using the chain rule and the fact that d/dx(sec(x)) = sec(x)tan(x), we have:

dy/dx = d/dx(sec(2x - 1))
= sec(2x - 1)tan(2x - 1) * d/dx(2x - 1)
= sec(2x - 1)tan(2x - 1) * 2

So the correct answer is: 2sec(2x - 1)tan(2x - 1).

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Answer:

  2120 ft³

Step-by-step explanation:

You want the volume of a hexagonal pyramid with side length 12 ft and height 17 ft.

The area of the base is given by the formula ...

  A = (3/2)√3·s² . . . . where s is the side length

  A = (3/2)√3·(12 ft)² = 216√3 ft²

The volume of a pyramid is given by the formula ...

  V = 1/3Bh

where B is the area of the base, and h is the height.

The volume of this pyramid is ...

  V = 1/3(216√3 ft²)(17 ft) ≈ 2120 ft³

The volume of the solid is about 2120 cubic feet.

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If Carl's GPA is 2.2, his GPA has a z score of -1.0. Carl's GPA has a z-score of -1, and he has a higher GPA than approximately 15.87% of other students at UTA.

To determine what percentage of other students at UTA Carl has a higher GPA than, we need to find the area under the normal curve to the right of his z score. We can use a standard normal table or calculator to find this value, which is approximately 0.1587 or 15.87%. Therefore, Carl has a higher GPA than about 15.87% of other students at UTA.

To answer your question, we'll first calculate Carl's z-score and then determine the percentage of students he has a higher GPA than.

1. Identify the given values: mean (M) = 2.7, standard deviation (SD) = 0.5, and Carl's GPA (score) = 2.2.
2. Calculate the deviation by subtracting the mean from Carl's GPA: deviation = score - M = 2.2 - 2.7 = -0.5.
3. Calculate Carl's z-score using the deviation and standard deviation: z-score = deviation / SD = -0.5 / 0.5 = -1.

Now that we have Carl's z-score (-1), we can use a z-table or calculator to find the percentage of students Carl has a higher GPA than.

4. Look up the z-score in a z-table or use a calculator to find the corresponding percentile: ~15.87%.

So, Carl's GPA has a z-score of -1, and he has a higher GPA than approximately 15.87% of other students at UTA.

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Answer:  The correct answer is a. The value of x is less than 16.

Step-by-step explanation:

a. The value of x is less than 16.

b The value of x is more than 16.

c The value of x is at most 16.

d The value of x is at least 16.

We will eliminate the choice of b and c because b is the description of x > 16, and c is the description of x ≥ 16.

The correct answer is a. The value of x is less than 16.

d would the description of x ≤ 16, meaning that is at least 16, meaning that x can be 16.

The hypothesis test or draw a conclusion about the sufficiency of evidence. comparing it to a critical value or obtaining a p-value. However, without specific data or sample information

In order to determine if there is sufficient evidence to support the mayor's claim, we need to set up the null and alternative hypotheses and conduct a hypothesis test.

Null hypothesis (H0): The proportion of residents favoring annexation is equal to or less than 72%.

Alternative hypothesis (H1): The proportion of residents favoring annexation is greater than 72%.

To test these hypotheses, we can use a one-sample proportion test. Let's denote p as the true proportion of residents favoring annexation in the population.

Given that the mayor believes more than 72% of the residents favor annexation, the alternative hypothesis is one-sided and can be stated as follows:

H0: p ≤ 0.72

H1: p > 0.72

To determine if there is sufficient evidence to support the mayor's claim, we would need to collect a sample from the town's residents and conduct a hypothesis test, using statistical methods such as calculating a test statistic (e.g., z-test) and comparing it to a critical value or obtaining a p-value. However, without specific data or sample information, we cannot perform the hypothesis test or draw a conclusion about the sufficiency of evidence.

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Option c, relevant quantitative factors, is the correct answer.

Direct materials and direct labor costs are factors that directly affect the production of a single product. They are important in determining the cost of producing the product and, therefore, are relevant quantitative factors that need to be considered when making a decision about whether to produce a product.

Qualitative factors, on the other hand, are non-monetary considerations such as market demand, competition, technological advancements, and environmental concerns, which may also impact the decision to produce a product, but are not directly related to the cost of production.

Therefore, in considering whether to produce a single product, both qualitative and quantitative factors need to be taken into account. However, direct materials and direct labor costs are relevant quantitative factors that are important in making an informed decision about the profitability of the product.

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We can say that the probability of observing a sample mean of 123.5 wpm or higher by chance alone, assuming the population means is 119 wpm and the standard deviation is 15 wpm, is 4.18%.

To solve this problem, we need to use the central limit theorem, which states that the distribution of sample means will be approximately normal, regardless of the underlying distribution, as long as the sample size is sufficiently large.

In this case, we have a population mean of 119 wpm and a standard deviation of 15 wpm. We want to know the probability that the sample mean would be greater than 123.5 wpm if 33-speed typists are randomly selected.

We can start by calculating the standard error of the mean, which is the standard deviation of the sample mean distribution. We can use the formula:

[tex]$SE = \frac{\sigma}{\sqrt{n}}$[/tex]

where SE is the standard error of the mean, σ is the population standard deviation, and n is the sample size.

Plugging in the values we have:

[tex]$SE = \frac{15}{\sqrt{33}} \approx 2.60$[/tex]

Next, we can calculate the z-score for a sample mean of 123.5 wpm using the formula:

[tex]$z = \frac{\bar{x} - \mu}{SE}$[/tex]

Plugging in the values we have:

z = (123.5 - 119) / 2.60 ≈ 1.73

Using a standard normal distribution table, we can find the probability that the z-score is greater than 1.73. This probability is approximately 0.0418.

Therefore, the probability that the sample mean would be greater than 123.5 wpm if 33-speed typists are randomly selected is approximately 0.0418 or 4.18% (rounded to four decimal places).

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Answer:

24

Step-by-step explanation:

posabaly 24 cause 8 times three is 24 and with these it's length times width

The fee for a private vehicle at Arches National Park during peak visiting time is $2.

Let's assume that v represents the fee for a private vehicle in dollars. According to the given information, the total earnings during peak visiting time at Arches National Park is $115,200. This amount is 3,600 times the sum of $30 and v.

To express this situation as an equation, we can set up the following equation:

115,200 = 3,600 * (30 + v)

We multiply the sum of $30 and v by 3,600 because the total earnings are 3,600 times that value. Solving this equation will give us the value of v, the fee for a private vehicle.

To solve the equation, we start by dividing both sides by 3,600:

115,200 / 3,600 = 30 + v

This simplifies to:

32 = 30 + v

Next, we subtract 30 from both sides to isolate v:

32 - 30 = v

2 = v

Therefore, the fee for a private vehicle at Arches National Park during peak visiting time is $2.

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The point on the parabola y=7 - x^2 that is closest to the point (7,7) is (-2,3).

To find the point on the parabola that is closest to the given point, we need to find the point on the parabola that has the minimum distance from the given point. This can be done by finding the distance between the given point and an arbitrary point (x, y) on the parabola, and then minimizing this distance by setting its derivative equal to zero. By solving the resulting equation, we can find that the point on the parabola that is closest to the given point is (-2,3).

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The first question requires finding the roots of a quadratic equation using factorization, the second question requires finding the derivative of a given function with respect to x, the third question requires calculating compound interest for a given period, and the fourth question requires finding the sum of the first 70 terms of an arithmetic progression.

To solve the quadratic equation x² + 3x - 28 = 0 using factorization, we need to find two numbers whose sum is 3 and whose product is -28. The two numbers are 7 and -4. Therefore, we can write the quadratic equation as (x + 7)(x - 4) = 0, which gives the roots x = -7 and x = 4.

To find the derivative of 2-2ut4 with respect to x, we need to treat t as a constant and apply the power rule of differentiation. The derivative is -8ut3(d/dx)(2-2ux) = -8ut3(-4u) = 32u2t3.

To find the compound interest for 3 years at 8,000.00 with an annual interest rate of 10%, we can use the formula A = P(1 + r/n)nt, where A is the total amount, P is the principal, r is the annual interest rate, n is the number of times interest is compounded per year, and t is the time in years. In this case, P = 8,000.00, r = 10%, n = 1 (since interest is compounded annually), and t = 3. Plugging in these values, we get A = 8,000.00(1 + 0.10/1)1(3) = 10,480.00. Therefore, the compound interest for 3 years is 2,480.00.

To find the sum of the first 70 terms of an arithmetic progression whose 10th and 12th terms are 50 and 65, respectively, we need to first find the common difference (d) and the first term (a1). Using the formula for the nth term of an arithmetic progression, we can write the equations a10 = a1 + 9d = 50 and a12 = a1 + 11d = 65. Solving these equations simultaneously, we get a1 = 22 and d = 3. Therefore, the sum of the first 70 terms is given by the formula S70 = (n/2)(2a1 + (n-1)d), where n = 70. Plugging in the values, we get S70 = (70/2)(2(22) + (70-1)3) = 3,955.

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We can start by expressing 64(cos 30° + i sin 30°) in polar form. We can plot these three points on the complex plane as vectors from the origin.

Recall that for any complex number z = x + yi, we have:

|z| = sqrt(x^2 + y^2) and arg(z) = tan^-1(y/x)

Using this formula, we have:

|64(cos 30° + i sin 30°)| = sqrt(64^2) = 64

arg(64(cos 30° + i sin 30°)) = tan^-1(sin 30° / cos 30°) = tan^-1(1/sqrt(3)) = π/6

So we can express 64(cos 30° + i sin 30°) in polar form as:

64(cos 30° + i sin 30°) = 64 cis (π/6)

To find the cube roots of this complex number, we can use De Moivre's theorem, which states that:

(cos θ + i sin θ)^n = cos(nθ) + i sin(nθ)

For any integer n. In particular, when n = 3, we have:

(cos θ + i sin θ)^3 = cos(3θ) + i sin(3θ)

So for our complex number 64 cis (π/6), we have:

(64 cis (π/6))^3 = 64^3 cis (3π/6) = 64^3 cis π = -64^3

So the cube roots of 64(cos 30° + i sin 30°) are the complex numbers z such that z^3 = 64(cos 30° + i sin 30°). We can find these roots by solving the equation z^3 = -64^3, which has three solutions:

z1 = 4 cis (π/3)

z2 = 4 cis π

z3 = 4 cis (5π/3)

Graphing these roots as vectors in the complex plane, we have:

z1 = 4 cis (π/3) = 2 + 2i√3

z2 = 4 cis π = -4

z3 = 4 cis (5π/3) = 2 - 2i√3

We can plot these three points on the complex plane as vectors from the origin, where the length of each vector corresponds to the magnitude of the complex number, and the angle from the positive real axis corresponds to the argument of the complex number. The resulting graph looks like an equilateral triangle with one vertex at the origin and the other two vertices at z1 and z3.

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(a) The value of m∠1 in the intersecting chords is 31.5⁰.

(b) The value of m∠2 in the intersecting chords is 139⁰.

(c) The value of m∠3 in the intersecting chords is 41⁰.

(d) The value of m∠4 in the intersecting chords is 93⁰.

(e) The value of m∠5 in the intersecting chords is 69.5⁰.

(f) The value of m∠6 in the intersecting chords is 69.5⁰.

The value of the missing angles is calculated by applying intersecting chord theorem, which states that the angle at tangent is half of the arc angle of the two intersecting chords.

The measure of angle 1 is calculated as follows;

arc angle opposite 72.5⁰ = 2 x 72.5⁰ = 145⁰

missing arc angle = 360 - ( 145⁰ + 139)

missing arc angle = 76⁰

m∠1 = ¹/₂ ( 139 - 76) (exterior angle of intersecting secants)

m∠1 = ¹/₂ (63) = 31.5⁰

The measure of angle 5 is calculated as;

m∠5 = ¹/₂ (139⁰)

m∠5 = 69.5⁰ (interior angle of intersecting secants)

The measure of angle 2 is calculated as;

m∠2 = 2 x m∠5 (angle at center is twice angle at circumference)

m∠2 = 2 x 69.5 = 139⁰

The measure of angle 6 is calculated as;

m∠6 = ¹/₂ (139⁰)

m∠6 = 69.5⁰ (interior angle of intersecting secants)

The measure of angle 3 is calculated as follows;

m∠3 = ¹/₂ ( (360 - 139) - 139) (exterior angle of intersecting secants)

m∠3 = ¹/₂ (221 - 139)

m∠3 = 41⁰

The measure of angle 4 is calculated as follows;

θ = 180 - (72.5 + m∠6)

= 180 - (72.5 + 69.5)

= 180 - 142

= 38

Each base angle of angle 2 = ¹/₂ (180 - 139) = 20.5⁰

= 38 - 20.5⁰

= 17.5⁰

m∠4 = 180 - (17.5⁰ + m∠5) (sum of angles in a triangle)

m∠4 = 180 - (17.5 + 69.5)

m∠4 = 93⁰

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A) A glass tank is filled with 4.5 liters of water. To make the water more like sea water, 1.99 grams of sodium chloride are added.

B) True or false: Sodium chloride is an electrolyte.

True. Sodium chloride is an electrolyte because it dissociates in water into sodium ions (Na+) and chloride ions (Cl-) which can conduct electricity.

C) What is the solute in this solution?

The solute in this solution is sodium chloride.

D) What is the solvent in this solution?

The solvent in this solution is water.

E) Which one is the right answer: What is the molarity of the resulting solution?

The molarity of the resulting solution can be calculated using the formula:

Molarity (M) = moles of solute / liters of solution

First, we need to convert the mass of sodium chloride added to moles. The molar mass of NaCl is 58.44 g/mol, so:

moles of NaCl = 1.99 g / 58.44 g/mol = 0.034 moles

The volume of the solution is 4.5 liters, so:

Molarity = 0.034 moles / 4.5 L = 0.0076 M

Therefore, the right answer is option c. 0.0076 M.

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The inverse of 51 modulo 99 is 49.

To find the inverse of 51 modulo 99, we need to find a number x such that (51 * x) % 99 = 1, where % represents the modulo operation.

One way to find the inverse is to use the extended Euclidean algorithm. However, in this case, we can observe that 51 * 49 = 2499, which is one more than a multiple of 99 (2499 = 99 * 25 + 24).

then, (51 * 49) % 99 = 24 % 99 = 24, which is equal to 1 modulo 99. Hence, the inverse of 51 modulo 99 is 49.

Therefore, the inverse of 51 modulo 99 is 49 because when 51 is multiplied by 49 and then taken modulo 99, the result is 1.

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The test statistic, rounded to 2 decimal places, is 0.79. To calculate the test statistic, we use the two-sample t-test formula, which takes into account the sample means, sample standard deviations, and sample sizes of the two groups.

In this case, we have a sample of 20 night students with a sample mean GPA of 2.82 and a standard deviation of 0.38, and a sample of 25 day students with a sample mean GPA of 2.77 and a standard deviation of 0.8.

We can calculate the pooled standard deviation, which is a weighted average of the two sample standard deviations, by using the formula:

sp = sqrt(((n1-1)s1^2 + (n2-1)s2^2)/(n1+n2-2))

where n1 and n2 are the sample sizes, and s1 and s2 are the sample standard deviations.

In this case, the pooled standard deviation is:

sp = sqrt(((20-1)(0.38)^2 + (25-1)(0.8)^2)/(20+25-2)) = 0.65

We can then calculate the t-statistic using the formula:

t = (x1 - x2) / (sp * sqrt(1/n1 + 1/n2))

where x1 and x2 are the sample means of the two groups, sp is the pooled standard deviation, and n1 and n2 are the sample sizes.

Plugging in the values, we get:

t = (2.82 - 2.77) / (0.65 * sqrt(1/20 + 1/25)) = 0.79

Therefore, the test statistic, rounded to 2 decimal places, is 0.79.

This means that the difference between the sample means of the two groups is not statistically significant at the 5% level, since the absolute value of the t-statistic is less than the critical value for a two-tailed t-test with 43 degrees of freedom at the 5% level.

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The type of sampling described in the scenario is known as systematic sampling.

Systematic sampling involves selecting elements from a population in a systematic and predetermined manner. In this case, the researcher is selecting every 20th name from the student directory to form her sample. This method of sampling is relatively simple to execute and can be less time-consuming compared to other methods such as random sampling. However, it is important to ensure that the selected interval does not coincide with any underlying patterns in the population that may bias the results.

Overall, systematic sampling can be a useful method for obtaining a representative sample from a large population, but it is important to consider the potential limitations and biases associated with this approach.

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Thus, the Wronskian for the set of functions {e^(4x), e^(-4x)} is 0.

To find the Wronskian for the set of functions {e^(4x), e^(-4x)}, you need to compute the determinant of a matrix formed by the functions and their first derivatives.

Let f(x) = e^(4x) and g(x) = e^(-4x). First, find the derivatives:

f'(x) = 4e^(4x)
g'(x) = -4e^(-4x)

Now, form a matrix and compute the determinant:

| f(x)  g(x)  |
| f'(x) g'(x) |

Wronskian = | e^(4x)  e^(-4x)  |
           |  4e^(4x) -4e^(-4x) |

Wronskian = (e^(4x) * -4e^(-4x)) - (e^(-4x) * 4e^(4x))
Wronskian = -4e^(4x - 4x) + 4e^(-4x + 4x) = -4 + 4 = 0

The Wronskian for the set of functions {e^(4x), e^(-4x)} is 0.

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Step-by-step explanation:

hope this helps if this wasn't what you looking for sorry