Answer:
19.84 m
Explanation:
The following data were obtained from the question:
Speed of sound (v) = 345 m/s
Time (t) = 0.115 s
Distance (x) =?
The distance of the object away can be obtained as follow:
v = 2x / t
345 = 2x / 0.115
Cross multiply
345 × 0.115 = 2x
39.675 = 2x
Divide both side by 2
x = 39.675 / 2
x = 19.84 m
Thus, the object is 19.84 m away from the camera.
Two 3 m long conductors are separated from each other by 5 mm and carry a current of 10 A dc. Calculate the force that one conductor exerts on the other.
Answer:
0.012 N
Explanation:
The formula to apply is that adopted from the Ampere law which is;
F= μ* I₁*I₂*l /2πd where
F is force that one conductor exerts on the other.
μ = magnetic permeability of free space = 4π×10⁻⁷ T. m/A
I₁ = current in conductor one=10 A
I₂ = current in conductor two= 10 A
l= length of conductor= 3 m
d= distance between the conductors = 5 mm = 0.005 m
Applying the values in the equation
F= 4π×10⁻⁷ *10*10*3 / 2π*0.005
F= 6 * 10⁻⁵ / 0.005
F=0.012 N
5.How do simple machines make work easier?(1 point)
a.They decrease the distance needed between a person and an object, allowing the person to apply more force and do more work.
b.They magnify the force being applied, thereby increasing the work they can do with no extra energy exerted by the person using the machine.
c.They reduce the amount of force needed to move an object to do the same amount of work.
d.They increase the distance over which a force is needed, doing more work with less force.
Answer:
They increase the distance over which a force is needed, doing more work with less force.
Explanation:
4. Friction is required for :
(a) Fast movement
(0) Both of the above
(b) Stopping the objec
(d) None of the above
Answer:
b) stopping the object
Explanation:
Friction always slows a moving object down. ... Friction can be a useful force because it prevents our shoes slipping on the pavement when we walk and stops car tyres skidding on the road. When you walk, friction is caused between the tread on shoes and the ground. This friction acts to grip the ground and prevent sliding
explanation of speed, velocity, instantaneous velocity, and acceleration. Discuss which ones are scalars, and which are vectors
Answer: See explanation
Explanation:
The scalar quantity has magnitude and isn't dependent on the direction. A vector quantity is dependent on the direction as well as the magnitude.
Speed: This is a scalar quantity as it has to do with the magnitude of an objects change in position.
Velocity: This is a vector quantity. It is the speed at which a particular object moves in a certain direction.
Instantaneous velocity: This is a vector quantity.
Acceleration: This is a vector. This is the rate at which velocity changes.
You have to deliver some 5.0-kg packages from your home to two locations. You drive for 2.0 h at 30 mi/h due east (call this segment 1 of your trip), then turn around and drive due west for 30 min at 28 mi/h (segment 2). Use a coordinate system with the positive x axis aimed toward the east and the origin at your home.
A. What is your position vector at the instant you reach the end of segment 1?
B. What is your position vector at the instant you reach the end of segment 2?
C. Calculate your displacement during segment 2.
Answer:
A. 60 mi.
B. 46 mi.
C. -14 mi.
Explanation:
A)
Assuming that we use a coordinate system with the positive x-axis aimed toward the east, and the origin at the start point, we can find the position vector at the end of the segment 1, applying the definition of average velocity, as follows:[tex]v_{avg1} = \frac{x_{1f} -x_{1o}}{t} (1)[/tex]
where x₁f = final position at the end of segment 1, x₁₀ = initial position at the start of the segment 1 = 0, t = time traveled during segment 1 = 2.0 h, and v₁, average velocity during segment 1 = 30 mi/h due east.Replacing by the givens, and solving for x₁f, we get:[tex]x_{1f} = v_{1avg} * t =30 mi/h * 2.0 h = 60 mi due east. (2)[/tex]
B)
In order to find the position at the end of the segment 2, we can use the same equation (1), but taking into account that the initial position will not be zero, but the final position at the end of the segment 1, i.e., 60 mi due east.Replacing by the givens, and solving for x₂f, we get:[tex]x_{2f} = x_{1f} + v_{2avg} * t = (-28 mi/h) * 0.5 h = 60 mi - 14 mi = 46 mi (3)[/tex]
C)
The displacement during the segment two, is simply the difference between the final and initial positions for this segment.Since x₂₀= x₁f = 60 mi, and x₂f = 46 mi, we find that the displacement is as follows:Δx = x₂f - x₂₀ = 46 mi - 60 mi = - 14 mi.A dog sees a flowerpot sail up and then back past a window H high. If the total time the pot is in sight is t seconds, find the height above the window that the pot rises. (Let H = 2 m and t = 1.0 s, find the height above the window-- after you have found an algebraic solution.)
Answer:
maximum height = 0.1225 m
Explanation:
given data
H = 2m
t = 1 sec
solution
we consider here velocity of pot at lower side is u
and final velocity is v with acceleration a
time take is t/2
so
height h = u × [tex]\frac{t}{2}[/tex] - 0.5 × g × [tex](\frac{t}{2})^2[/tex] .................1
here
u = [tex]\frac{2}{t} \times ( h + \frac{gt^2}{8} )[/tex]
and
v = u +a t/2 .........................2
v = u + g t/2
v = [tex]\frac{2h}{t} + \frac{gt}{4} - \frac{gt}{2}[/tex]
v = [tex]\frac{2h}{t} - \frac{gt}{4}[/tex]
so that
maximum height is = [tex]\frac{v^2}{2g}[/tex]
maximum height = [tex]\frac{(\frac{2h}{t} - \frac{gt}{4})^2}{2g}[/tex]
put here value of h and t
maximum height = [tex]\frac{(\frac{2(2)}{1} - \frac{g(1)}{4})^2}{2g}[/tex]
maximum height = 0.1225 m
Part B.
Light and sound are two very different phenomena. However, both exhibit wave characteristics, such as frequency. For
sound waves, when the frequency changes, the pitch is affected. Using the diagrams above as a reference, determine
how visible light is affected by changes in frequency
Answer:
for Visible light, changing the frequency will change the color
Explanation:
edmentum
Answer:
For Visible light, changing the frequency will change the color.
In which three ways does the pattern seen on the screen during a double-slit
experiment support the wave model of light?
O A. All of the light that enters the slits passes through them.
B. The light bends around the edges of the slit.
C. There are bands of dimmer light.
D. There are bands of brighter light.
Answer:
b,c,d
Explanation:
the light bends around the edges of the slit
there are bands of brigter light
there are bands of dimmer light
( just took the quiz )
Option B,C and D shows the three ways does the pattern seen on the screen during a double-slit experiment.
What is double-slit experiment?The double-slit experiment shows that light and matter may have properties that are both conventionally defined waves and particles, as well as the essentially probabilistic nature of quantum mechanical processes.
The three ways does the pattern seen on the screen during a double-slit experiment support the wave model of light;
B. The light bends around the edges of the slit.
C. There are bands of dimmer light.
D. There are bands of brighter light.
Hence, B,C and D are the three ways does the pattern seen on the screen during a double-slit experiment.
To learn more about the double-slit experiment, refer to the link;
https://brainly.com/question/17167388
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3. What is the main difference between a physical change and a chemical
change?
A. Physical changes alter the composition whereas chemical changes alter the
appearance of a substance.
B. Physical changes describe the appearance of a substance whereas chemical
changes describe qualities only observed with a reaction.
C. Physical changes describe qualities only observed with a reaction whereas
chemical changes describe the appearance of a substance.
D. Physical changes alter the appearance whereas chemical changes alter the
composition of a substance,
Answer:
B and D could both be right as they are quit similar.
Consider two rods of the same length and diameter,
Increasing the diameter of one would change the expansion qualities of that rod even though there would be no chemical changes,
However, leaving the physical appearance of both rods the same while applying a reactive substance (acid or something) to one of the rods would not necessarily change the physical appearance of that rod but could make a considerable change in the physical properties of that rod.
You are arranging family members for a photograph, and you want them to stand in order of increasing height. Your uncle is half a foot shorter than your aunt, who is taller than your cousin. Your grandmother is 2 in. shorter than your grandfather. Your brother is 1 in. taller than your aunt and 3 in. taller than your cousin. Your grandfather is 1 cm taller than your aunt.
List the relatives in order of increasing height.
Answer:
Uncle , Cousin, Grandmother , Aunt , Brother , Grandfather
Explanation:
Arranging in the order of increasing height simply means starting from the shortest to the tallest ( ascending order )
Number of relatives = 6
Uncle , Aunt , cousin, grandmother , grandfather, Brother
First lets write out the relationship between your relatives using a feet as our S.I unit
Uncle is shorter than Aunt by ; 1/2 feet = 0.5 feet
Cousin is shorter than Aunt by : unknown value
Cousin is shorter than Brother by ; 1/4 feet = 0.25 feet
Grandmother is shorter than Grandfather by ; 0.16 feet
Aunt is shorter than Grandfather by ; 0.03 feet
Aunt is shorter than brother by ; 0.08 feet
Hence the list of relatives in ascending order
Uncle , Cousin, Grandmother , Aunt , Brother , Grandfather
(a)Uncle is taller than cousin.
(b)Relatives in order of increasing height will be Uncle , Cousin, Grandmother , Aunt , Brother , Grandfather.
What is ascending order ?Ascending order is a way of organizing integers in ascending order from lowest to biggest value. The sequence is from left to right.
The given number of relative is 6 which is uncle , aunt , cousin, grandmother , grandfather, brother.
1.Uncle is shorter than Aunt by ; 1/2 feet = 0.5 feet
2.Cousin is shorter than Aunt by : unknown value
3.Cousin is shorter than Brother by ; 1/4 feet = 0.25 feet
4.Grandmother is shorter than Grandfather by ; 0.16 feet
5.Aunt is shorter than Grandfather by ; 0.03 feet
6.Aunt is shorter than brother by ; 0.08 feet
Hence relatives in order of increasing height will be Uncle , Cousin, Grandmother , Aunt , Brother , Grandfather.
To learn more about the ascending order refer to the link;
https://brainly.com/question/1477877
In an experiment, a cement block of mass 14 kg was placed on top of 8 (carefully arranged) eggs without breaking the eggs.
1) Calculate the force per egg caused by the weight of the block.
2) If the pressure on each egg is 25 N/mm 2 , calculate the contact area, in mm 2 , between the block and one egg.
Answer:
1) The force per egg caused by the weight of the block is 17.15 N
2) [tex]A= 0.686\ mm^2[/tex]
Explanation:
Pressure
The pressure is computed as the force acting upon a surface divided by the area of the surface :
[tex]P=\frac{F}{A}[/tex]
The weight of an object of mass m is:
W = mg
Where g is the gravitational acceleration of [tex]9.8\ m/s^2[/tex]
The cement block has a mass of m=14 kg, thus its weight is:
W = 14*9.8
W = 137.2 N
1) This weight is evenly distributed over the 8 eggs, thus the force per egg is:
F = 137.2 N/8= 17.15 N
The force per egg caused by the weight of the block is 17.15 N
2) It's given the pressure on each egg as [tex]P= 25 \ N/mm^2[/tex] and we know the force acting on each one is F=17.15 N. To find the contact area we solve the formula of the pressure for A:
[tex]\displaystyle A=\frac{F}{P}[/tex]
[tex]\displaystyle A=\frac{17.15}{25}[/tex]
[tex]\mathbf{A= 0.686\ mm^2}[/tex]
Explain how air pollution impacts each of Earth's systems.
1) Atmosphere
2) Lithosphere
3) Biosphere
4) Hydrosphere
Answer:
1) Atmosphere
Explanation: because if you think about it the only real explaination is atmosphere.
which of the following are not units used to measure energy?
a. joules
b. newtons
c. BTU
d. calories
Answer:
The BTU, or British thermal unit, is actually a measure of heat.
Aaron walks from the front door to the mailbox at the end of his 8 m driveway. What
is Aaron's displacement? Distance traveled?
(Hint: Displacement has a direction)
Answer:
8m
8m towards the mailbox
Explanation:
Given parameters:
Length of path = 8m
Unknown:
Distance = ?
Displacement = ?
Solution:
Distance is the length of path and it has magnitude but no direction.
The distance covered is 8m
Displacement is the length of path and it has magnitude and direction.
Displacement is 8m towards the mailbox
You're driving down the highway late one night at 20 m/s when a deer steps onto the road 39 m in front of you. Your reaction time before stepping on the brakes is 0.50 s , and the maximum deceleration of your car is 11 m/s2.
a. How much distance is between you and the deer when you come to a stop?
b. What is the maximum speed you could have and still not hit the deer?
Answer:
a) 10.8 m
b) 24.3 m/s
Explanation:
a)
In order to get the total distance traveled since you see the deer till the car comes to an stop, we need to take into account that this distance will be composed of two parts.The first one, is the distance traveled at a constant speed, before stepping on the brakes, which lasted the same time that the reaction time, i.e., 0.5 sec.We can find this distance simply applying the definition of average velocity, as follows:[tex]\Delta x_{1} = v_{1o} * t_{react} = 20 m/s * 0.5 s = 10 m (1)[/tex]
The second part, is the distance traveled while decelerating at -11 m/s2, from 20 m/s to 0.We can find this part using the following kinematic equation (assuming that the deceleration keeps the same all time):[tex]v_{1f} ^{2} - v_{1o} ^{2} = 2* a* \Delta x (2)[/tex]
where v₁f = 0, v₁₀ = 20 m/s, a = -11 m/s².Solving for Δx, we get:[tex]\Delta x_{2} = \frac{-(20m/s)^{2}}{2*(-11m/s)} = 18.2 m (3)[/tex]
So, the total distance traveled was the sum of (1) and (3):Δx = Δx₁ + Δx₂ = 10 m + 18.2 m = 28.2 m (4)Since the initial distance between the car and the deer was 39 m, after travelling 28.2 m, the car was at 10.8 m from the deer when it came to a complete stop.b)
We need to find the maximum speed, taking into account, that in the same way that in a) we will have some distance traveled at a constant speed, and another distance traveled while decelerating.The difference, in this case, is that the total distance must be the same initial distance between the car and the deer, 39 m.⇒Δx = Δx₁ + Δx₂ = 39 m. (5)Δx₁, is the distance traveled at a constant speed during the reaction time, so we can express it as follows:[tex]\Delta x_{1} = v_{omax} * t_{react} = 0.5* v_{omax} (6)[/tex]
Δx₂, is the distance traveled while decelerating, and can be obtained using (2):[tex]v_{omax} ^{2} = 2* a* \Delta x_{2} (7)[/tex]
Solving for Δx₂, we get:[tex]\Delta x_{2} = \frac{-v_{omax} ^{2} x}{2*a} = \frac{-v_{omax} ^{2}}{(-22m/s2)} (8)[/tex]
Replacing (6) and (8) in (5), we get a quadratic equation with v₀max as the unknown.Taking the positive root in the quadratic formula, we get the following value for vomax:v₀max = 24.3 m/s.A plane drops a package for delivery. The plane is flying horizontally at a speed of 120\,\dfrac{\text m}{\text s}120 s m 120, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction, and the package travels 255\,\text m255m255, start text, m, end text horizontally during the drop. We can ignore air resistance.
Answer:
-22.1
Explanation:
1 / 4
Step 1. List horizontal (xxx) and vertical (yyy) variables
xxx-direction yyy-direction
t=\text?t=?t, equals, start text, question mark, end text t=\text?t=?t, equals, start text, question mark, end text
a_x=0a
x
=0a, start subscript, x, end subscript, equals, 0 a_y=-9.8\,\dfrac{\text m}{\text s^2}a
y
=−9.8
s
2
m
a, start subscript, y, end subscript, equals, minus, 9, point, 8, start fraction, start text, m, end text, divided by, start text, s, end text, squared, end fraction
\Delta x=255\,\text mΔx=255mdelta, x, equals, 255, start text, m, end text \Delta y=\text ?Δy=?delta, y, equals, start text, question mark, end text
v_x=v_{0x}v
x
=v
0x
v, start subscript, x, end subscript, equals, v, start subscript, 0, x, end subscript v_y=?v
y
=?v, start subscript, y, end subscript, equals, question mark
v_{0x}=120\,\dfrac{\text m}{\text s}v
0x
=120
s
m
v, start subscript, 0, x, end subscript, equals, 120, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction v_{0y}=0v
0y
=0v, start subscript, 0, y, end subscript, equals, 0
Note that there is no horizontal acceleration, so v_x=v_{0x}v
x
=v
0x
v, start subscript, x, end subscript, equals, v, start subscript, 0, x, end subscript. The time is the same for the xxx and yyy directions.
Also, the package has no initial vertical velocity.
Our yyy-direction variable list has too many unknowns to solve for \Delta yΔydelta, y directly. Since both the yyy- and xxx-directions have the same time ttt and horizontal acceleration is zero, we can solve for ttt from the xxx-direction motion by using equation:
\Delta x=v_xtΔx=v
x
tdelta, x, equals, v, start subscript, x, end subscript, t
Once we know ttt, we can solve for \Delta yΔydelta, y using the kinematic equation that does not include the unknown variable v_yv
y
v, start subscript, y, end subscript:
\Delta y=v_{0y}t+\dfrac {1}{2}a_yt^2Δy=v
0y
t+
2
1
a
y
t
2
delta, y, equals, v, start subscript, 0, y, end subscript, t, plus, start fraction, 1, divided by, 2, end fraction, a, start subscript, y, end subscript, t, squared
Hint #22 / 4
Step 2. Find ttt from horizontal variables
\begin{aligned}\Delta x&=v_xt \\\\ t&=\dfrac{\Delta x}{v_{0x}} \\\\ t&=\dfrac{255\,\text m}{120\dfrac{\text m}{\text s}} \\\\ &=2.125\,\text s \end{aligned}
Δx
t
t
=v
x
t
=
v
0x
Δx
=
120
s
m
255m
=2.125s
Hint #33 / 4
Step 3. Find \Delta yΔydelta, y using ttt
Using ttt to solve for \Delta yΔydelta, y gives:
\begin{aligned}\Delta y&=v_{0y}t+\dfrac{1}{2}a_yt^2 \\\\ &=\cancel{ (0 )t}+\dfrac{1}{2}\left (-9.8\dfrac{\text m}{\text s^2}\right )\left(2.125\,\text s\right)^2 \\\\ &=-22.1\,\text m \end{aligned}
Δy
=v
0y
t+
2
1
a
y
t
2
=
(0)t
+
2
1
(−9.8
s
2
m
)(2.125s)
2
=−22.1m
Hint #44 / 4
The correct answer is -22.1\,\text m−22.1mminus, 22, point, 1, start text, m, end text.
A baby crawls 3m in 6s. The baby travels toward the west. Calculate the velocity of the baby.
Answer:
.5m per second to the west
Explanation:
distance divided by time
When catching a baseball, a catcher's glove moves by 11 cm along the line of motion of the ball. If the baseball exerts a force of 464 N on the glove, how much work is done by the ball
Answer:
51.04 joules
Explanation:
The movement by the gloves = 11cm
Force by the baseball = 464N
First of all we are going to convert cm to metres
11cm = 11/100 meters = 0.11m
The formula for workdone is given as:
W = f x d
W = workdone
F = force
D = distance
Workdone = 464 x 0.11
= 51.04 joules
The workdone by the ball is 51.04 joules
Thank you
5. A man in a car is listening to the radio. The radio station is broadcasting at a frequency of 85 MHz from two radio transmitters immediately behind and immediately in front of the car. At 11.30 am he has excellent reception, but 15 minutes later is has terrible reception. How fast is the car going
Answer:
Speed = 0.00392 m/s
Explanation:
Solution:
Frequency of the radio = 85 MHz
If we have the frequency, we can calculate the wavelength of the radio wave.
As we know,
Frequency = speed of light/wavelength
wavelength = c/f
c = speed of light = 3 x [tex]10^{8}[/tex] m/s
So,
Wavelength = 3 x [tex]10^{8}[/tex] m/s / 85 x [tex]10^{6}[/tex] Hz
Wavelength = 3.5294 m
Man gets disturbed reception at t = 15 min
t = 15 x 60 = 900 s
t = 900 s
Speed = distance/time
Here, distance is wavelength. So,
Speed = 3.5294 m / 900 s
Speed = 0.00392 m/s
Hence, the man's car is going with speed of 0.00392 m/s
The volume of a solid object tends to increase as its temperature increases. Which quantities determine how large the change in volume is
Answer:
I. The change in temperature of the object.
II. The initial volume of the object.
Explanation:
Generally, the volume of a solid object tends to increase as its temperature increases and this phenomenon is known as thermal expansion.
Hence, the quantities which determine how large the change in volume of a solid object is includes;
I. The change in temperature of the object.
II. The initial volume of the object.
This ultimately implies that, when a solid object is heated, the atoms of the object vibrate rapidly about their fixed points and thus, causing an increase in the volume of the object.
In conclusion, this scientific phenomenon known as thermal expansion is valid and true for all the three (3) states of matter;
Solid. Liquid. Gas.OFFERING 60 POINTS IF YOU CAN SHOW THE WORK!!!!
A 1000 kg roller coaster begins on a 10 m tall hill with an initial velocity of 6m/s and travels down before traveling up a second hill. As the coaster moves from its initial height to its lowest position, 1700J of energy is transformed to thermal energy by friction.
Answer; 10.6 i think
Explanation:
(a) At the top of the hill, the coaster has total energy (potential and kinetic)
E = (1000 kg) g (10 m) + 1/2 (1000 kg) (6 m/s)² = 116,000 J
As it reaches its lowest position, its potential energy is converted to kinetic energy, and some is lost to friction, making its speed v such that
1/2 (1000 kg) v ² = 116,000 J - 1700 J = 114,300 J
===> v ≈ 15.2 m/s
If no energy is lost to friction as the coaster makes its way up the second hill, all of its kinetic energy would be converted to potential energy at the maximum possible height H.
1/2 (1000 kg) (15.2 m/s)² = (1000 kg) g H
===> H ≈ 11.7 m
(b) At the top of the second hill with minimum height h, and with maximum speed 4.6 m/s, the coaster has energy
E = P + K = (1000 kg) g h + 1/2 (1000 kg) (4.6 m/s)²
Assuming friction isn't a factor again, the energy here should match the energy at the lowest point in part (a), 114,300 J.
(1000 kg) g h + 1/2 (1000 kg) (4.6 m/s)² = 114,300 J
===> h ≈ 10.6 m
3) Given R, = 4 ohms and R, = 5 ohm and V = 18 volts
d) Find the total resistance: I
Find the current in the circuit:
f) Find the voltage drop in each resistor:
Answer:
d) the total resistance is 4 + 5 = 9 ( ohm)
e) the current in the circuit is 18/9 = 2(A)
f) the voltage in R = 4 ohm is 2.4 = 8 (V)
the voltage in R = 5 ohm is 18 - 8 = 10 (V)
An object of mass 5kg travels in the positive direction with a speed of 1ms. The object collides with a second object that exerts an average net force over an interval of time such that the 5kg object comes to rest. Which of the following best predicts the change in momentum for the 5kg object?
A. The change in momentum is in the negative direction.
B. The change in momentum is in the positive direction.
C. The change in momentum is zero.
D. The direction of the change in momentum cannot be determined without knowing the value of the average force and time in which the force is exerted.
Answer: C. The change in momentum is zero.
Explanation: When an object is in movement, to change its direction or speed we have to applied a force for determine amount of time. This change is called Change in Momentum or Impulse.
Change in momentum is a derivation of Newton's Second Law and can written as
[tex]F.t=m.\Delta v[/tex]
So, for the case discussed, object of mass 5kg already has momentum because it is already in motion. When another object collides with, applying a force for an interval of time, there is a change in momentum for the first object. Since the object stopped, it means velocity is 0, so as it is described in the formula, change in momentum is also 0.
In conclusion, "The change in momentum is zero" is the best prediction.
Padded dashboards in cars are safer in an accident than nonpadded ones because an occupant hitting the dash has:________.
(a) increased time of impact.
(b) decreased impulse.
(c) decreased impact force.
(d) a and b above.
(e) a and c above.
Answer:
(e) a and c above.
Explanation:
Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.
Mathematically, momentum is given by the formula;
[tex] Momentum = Mass * Velocity [/tex]
The law of conservation of momentum states that the total linear momentum of any closed system would always remain constant with respect to time.
Padded dashboards in cars are safer in an accident than non-padded ones because an occupant hitting the dashboard of an automobile car has an increased time of impact and a decreased impact force because the force or shock experienced is high and happens rapidly over a short period of time, thus, the occupant has less time and velocity while absorbing the momentum of the car in the course of the collision.
Ball X of mass 1.0 kg and ball Y of mass 0.5kg travel toward each other on a horizontal surface. Both balls travel with a constant speed of 5 m/s until they collide. During the collision, ball Y exerts an average force with a magnitude of 40N for 1/6s on ball X . Which of the following best predicts ball momentum after the collision?
A. Ball Y will travel at a speed less than 5 m/s in the same direction of travel as before the collision.
B. Ball Y will travel at a speed less than 5 m/s in the opposite direction of travel as before the collision.
C. Ball will travel at a speed greater than 5 m/s in the same direction of travel as before the collision.
D. Ball Y motion cannot be predicted because the impulse on it is not known.
Answer:
C
Explanation:
Ball Y will travel at a speed greater than 5 m/s in the opposite direction of travel as before the collision.
The ball Y will travel at a speed greater than 5 m/s in the same direction of travel as before the collision.
The given parameters;
mass of ball X = 1 kgmass of ball Y = 0.5 kgspeed of the two balls after collision, v = 5 m/sforce exerted by ball Y, = 40 Ntime, t = 1/6 sApply the principle of conservation of linear momentum. The total momentum of the balls before collision must equal total momentum after collision.
[tex]m_xv_x_1 + m_yv_y_1 = m_x v_x_2 + m_yv_y_2\\\\m_xv_x_2 - m_xv_x_1 = -(m_yv_y_2 - m_yv_y_1)\\\\\Delta P_x = - \Delta P_y[/tex]
The impulse experienced by ball Y is calculated as follows;
[tex]\Delta P_y = m_yv_y_2- m_yv_y_1 = Ft = 40 \times \frac{1}{6} = 6.67 \ kgm/s[/tex]
The final speed of ball Y is calculated as follows;
[tex]m_yv_y_2 - m_yv_y_1 = 6.67 \\\\m_yv_y_2 = 6.67 + m_yv_y_1\\\\0.5(v_y_2) = 6.67 + (0.5 \times 5)\\\\0.5(v_y_2) = 9.17\\\\v_y_2 = \frac{9.17}{0.5} \\\\v_y_2 = 18.34 \ m/s[/tex]
Thus, the ball Y will travel at a speed greater than 5 m/s in the same direction of travel as before the collision.
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A projectile is launched with an initial velocity of
200 meters per second at an angle of 30° above the
horizontal. What is the magnitude of the vertical
component of the projectile's initial velocity by?
(1) 200 m/s x cos 30°
(2) 200 m/s X sin 30°
(3) (200 m/s)/(cos 30 °)
(4) (200 m/s)/(sin 30 °)
The magnitude of the vertical component of the projectile's initial velocity is 200 m/s × sin 30°.
The diagrammatic representation of the velocity of the projectile can be seen in the attached image below.
From the diagram, let consider the ΔOAP where Vector OP makes an ∠θ = 30° to the horizontal x-axis.
where;
|OP| = magnitude of projectile velocity|OA| = magnitude of the horizontal component|OB|/|AP| = vertical component of the projectile∴
Using trigonometric approach for ΔOAP;
[tex]\mathbf{sin\theta = \dfrac{AP}{OP}}[/tex]
[tex]\mathbf{AP =OP\times sin \theta}}[/tex]
AP = 200 × sin 30°
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A 1.8 m tallman stand in an elevator accelerating upward at 12 m/s?,
what is the blood pressure in the brain and foot.
Take the height difference between the heart and the brain to be
0.35 m?
13.3 x 103 Pa] & [Pblood = 1060 kg.m-3]
Note: [: P Heart
Answer:
12.483 Kpa
46.806 Kpa
Explanation:
Man's height = 1.8m
Pheart = 13.3 * 10^3
Density of blood (ρ) = 1060 kg/m³
Height difference between heart and brain (Hh - Hb) = 0.35m
g = acceleration due to gravity = 9.8 m/s²
Acceleration (a) = 12 m/s²
Blood pressure in brain :
Pbrain = Pheart - ρ(a - g) * (Hh - Hb)
Pbrain = 13.3 * 10^3 - 1060(12 - 9.8) * 0.35
Pbrain = 13300 - (2332 * 0.35)
Pbrain = 13300 - 816.2
Pbrain = 12483.8 pascal = 12.483 Kpa
Blood pressure in feet :
Pbrain = Pheart + ρ(a + g) * 1.8 - (Hh - Hb)
Pbrain = 13.3 * 10^3 + 1060(12 + 9.8)*(1.8 - 0.35)
Pbrain = 13300 + 1060(21.8 * 1.45)
Pbrain = 13300 + 33506.6
Pbrain = 46806.6 pascal = 46.806 Kpa
A student is transmitting sound waves through various materials. Through which metal in the table will the sound waves travel the fastest? Aluminum Copper Lead Brass (70% Cu, 30% Zn) 6,420 4,700 5,010 1,960 Speed of sound (m/s) O
A. Brass O
B. Aluminum
C. Copper O
D. Lead
Answer:
Aluminum
Explanation:
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Answer:aluminum
Explanation:
A hockey puck slides across the ice and eventually comes to a stop. Why did the puck stop?
Answer: the total energy of the puck, ice surface, and surrounding air decreases to zero
Explanation:
A hockey puck slides across the ice and eventually comes to a stop because of friction between surface of the puck and ice surface.
What is Friction ?Friction is a resistance to motion of the object. for example, when a body slides on horizontal surface in positive x direction, it has friction in negative x direction and that measure of friction is a frictional force. frictional force is directly proportional to the Normal(N). i.e. [tex]F_{fri}[/tex] ∝ N
[tex]F_{fri}[/tex] = μN where μ is called as coefficient of the friction. It is a dimensionless quantity.
When a body is kept on horizontal surface, its normal will be straight upward which is reaction of mg. i.e. N=mg.
Frictional force is equal to
[tex]F_{fri}[/tex] = μmg
When hockey puck slides across the ice, friction between surface of puck and surface of ice produces resistance to the motion of the puck, due to resistance puck slow down slowly and eventually come to a stop. Motion and frictional force are opposite to each other. we can calculated the exact value of frictional force when we know the coefficient of friction between puck and ice surface.
hence due to friction, puck come to a stop
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A pendulum with a mass of 1 kg is released from a height of 1.5 cm above the height of its resting position. How fast will the pendulum be moving when it passes through the lowest point of its swing?
Answer:
v = 0.54 m/s
Explanation:
The Principle Of Conservation Of Mechanical Energy
In the absence of friction, the total mechanical energy is conserved. That means that
Em=U+K is constant, being U the potential energy and K the kinetic energy
U=mgh
[tex]\displaystyle K=\frac{mv^2}{2}[/tex]
When the mass (m=1 kg) of the pendulum is at the top of the path at a height of h=1.5 cm=0.015 m, its kinetic energy is 0 and its potential energy is:
U=1 * 9.8 * 0.015 = 0.147 J
That potential energy is completely transformed into kinetic energy at the bottom of the swing. The speed can be calculated by solving for v:
[tex]\displaystyle \frac{mv^2}{2}=0.147[/tex]
Multiplying by 2 and dividing by m:
[tex]\displaystyle v^2=\frac{2K}{m}[/tex]
[tex]\displaystyle v^2=\frac{2*0.147}{1}=0.294[/tex]
[tex]v=\sqrt{0.294}[/tex]
v = 0.54 m/s