1. A quarterback passes a football at a velocity of 15.2 m/s at an angle of 40° to the horizontal
toward an intended receiver 27.4 m downfield. The pass is released 1.3 m above the ground. Assume
that the receiver is stationary. Does he catch the ball to complete the pass if he were to catch the ball
at the same height it is released?

If the contacts on a manual starter cannot be closed immediately after a motor overload has tripped them open, the probable reason is that the thermal overload device (a type of overload relay) has not had enough time to cool down.

The thermal overload device is designed to protect the motor from damage by sensing the temperature of the motor windings and tripping the starter if the temperature becomes too high.

The contacts of the starter will remain open until the thermal overload device has cooled down enough to reset, which typically takes several minutes.

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The plant can convert fuel energy into power with an efficiency of about 30% for 241 days .

As per the data given in the above question are as bellow,

We need to know how much fuel is in the plant in order

To calculate how many days a 3 GW power plant can run on fuel containing U-235 and U-238.

Assume the facility contains 1 metric tonne of U-235 and U-238-containing fuel.

The total energy released from the fission if all of the U-235 and U-238 split would be

200 MeV/fission * 2.51021 fissions/metric tonne = 51023 MeV.

The total energy transferred to electricity would be

51023 MeV * 0.3 = 1.51023 MeV = 1.51016 J

if we assume a 30% efficiency.

It would require 1.51016 J / 3109 J/s or 5106 s or 5,800 hours or 241 days to generate 3 GW at the power plant.

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The linear curve of the graphs shows an increase in distance of 5 m within 2 seconds. Then , the distance within 5 seconds will be 12.5m and the instantaneous speed is 2.5 m/s.

Instantaneous speed of an object is the speed at a particular instant. It describes how far an object travelled at a particular moment in time.

It is given that, the graph shows linearity in curve , where for each 2 second time interval the monkey climbs 5m. Then, for a time interval of 5 seconds, the monkey will climb 12.5 m in the tree.

Instantaneous speed = distance/time

t= 5 s

d = 12.5 m

then v = 12.5/5 = 2.5 m/s

Therefore, the instantaneous speed of the monkey within the given time will be 2.5 m/s.

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7.2 gallons of oil is needed to generate the electricity needed to keep 100-watt light bulb lit for one year if the overall efficiency of generating station is 30%.

Ratio of the work performed by machine or in process to the total energy expended / heat consumed is called as efficiency.

Energy consumed is 100 W * 8760 h = 876,000 Wh = 876 kWh.

Given, overall efficiency of the generating station is 30%, which means that only 30% of energy in the fuel is converted into usable electricity. So, for every 1 unit of energy in fuel, 0.3 units of energy are generated as electricity.

To find out how much oil is needed, we need to divide total energy consumed by the light bulb (876 kWh) by the overall efficiency of the generating station (0.3). So, 876 kWh / 0.3 = 2920 kWh

Now we need to convert the energy consumption in kWh to gallons of oil,

2920 kWh = 2920 * 3412 Btu/kWh = 1,000,944 Btu

1,000,944 Btu / 138,690 Btu/gal = 7.2 gallons

Therefore, 7.2 gallons of oil is needed to generate the electricity needed to keep 100-watt light bulb lit for one year.

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The line charge density on a long wire if the electric field 45 cm from the wire has magnitude 240 kn/c and points toward the wire is  2.08 x 10-7 C/m.

Calculating the line charge density of a long wire is a simple process. To begin, we need to know the magnitude of the electric field at a given distance from the wire. In this case, the electric field 45 cm from the wire has a magnitude of 240 kn/c and points toward the wire.

Using this information, we can calculate the line charge density of the wire using the equation:

Line charge density (λ) = Electric field (E) * Permittivity of free space (ε0) / 2π * distance (r)

Plugging in the values, we get:

λ = 240 kn/c * 8.85 x 10-12 C2/Nm2 / 2π * 0.45m

Solving this equation, we get a line charge density of 2.08 x 10-7 C/m.

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The sound waves produced by the engine have a frequency of 120 Hz.

To calculate the frequency of the sound waves produced by the engine, we can use the following formula:

f = 1/T

where f is the frequency and T is the period of the sound wave.

Sound waves have a period of 8.3 milliseconds, so we can plug this value into the equation to find the frequency.

f = 1 / (8.3 x 10^-3s)

f = 120 hertz

Therefore, the sound waves produced by the engine have a frequency of 120 Hz.

It is important to note that frequency is the number of wave oscillations or cycles that occur in a unit of time and is measured in hertz (Hz). The period is the time of one oscillation and is the reciprocal of the frequency. The lower the frequency, the longer the period and vice versa.

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Answer:

D. Smog

Explanation:

The phenomenon caused by the excessive release of smoke by factories, burning garbage, and vehicles is known as smog.

Pressure acts in all direction .

What is the fundamental meaning of pressure?

The amount of force applied to a unit area is referred to as pressure. The weight of the water column above contributes to the pressure in a liquid. This pressure works in all directions because a liquid's particles are closely packed. For instance, the pressure exerted on a dam at a reservoir's bottom is larger than the pressure exerted near the top.

There is a magnitude to pressure, but no accompanying direction. At one location inside a gas, pressure spreads out in all directions. The pressure force acts perpendicular to the surface at a gas's surface.

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(a) The gravitational force between the two large masses is 1.37 x 10⁻⁵ N.

(b) The distance from 290 kg mass in which 23.9 kg mass experiences a zero net force is 0.24 m.

The gravitational force between the two large masses is calculated as follows;

F = (Gm₁m₂ ) / R²

where;

F = ( 6.672 x 10⁻¹¹ x 111 x 290 ) / ( 0.396² )

F = 1.37 x 10⁻⁵ N

The distance from 290 kg mass in which 23.9 kg mass experiences a zero net force is calculated as;

Let the distance between 290 kg and 23.9 kg = d

F1 = ( 6.672 x 10⁻¹¹ x 23.9 x 290 ) / ( d² )

F1 = ( 4.62 x 10⁻⁷ ) / d²

F2 = ( 6.672 x 10⁻¹¹ x 23.9 x 111 ) / ( 0.396 - d )²

F2 = ( 1.77 x 10⁻⁷ ) /  ( 0.396 - d )²

( 4.62 x 10⁻⁷ ) / d² = ( 1.77 x 10⁻⁷ ) /  ( 0.396 - d )²

( 4.62 x 10⁻⁷ )(0.396 - d )² =  ( 1.77 x 10⁻⁷ )d²

2.6(0.396 - d )²  = d²

(0.396 - d )²   = d²/2.6

0.396 - d = √ (d²/2.6)

0.396 - d = 0.62d

0.396 = 1.62d

d = 0.396 / 1.62

d = 0.24 m

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Formula for momentum:

[tex]p=mv[/tex]

momentum(measured in kg*m/s) = mass(measured in kg) * velocity(measured in m/s)

__________________________________________________________

Given:

[tex]m=1650kg[/tex]

[tex]v=42m/s[/tex]

[tex]p=?[/tex]

__________________________________________________________

Finding momentum:

[tex]p=mv[/tex]

[tex]p=1650\times42[/tex]

__________________________________________________________

Answer:

[tex]\fbox{p = 69,300 kg*m/s}[/tex]

The angle which is calculated below the horizontal of the velocity of the puck just before it hits the ground is 12.60°.

Given the following data:

Initial velocity = 28.0 m/s

Acceleration due to gravity = 9.81

Displacement (height) = 2.00 meters.

Let us calculate and determine the angle below the horizontal of the velocity of the puck just before it hits the ground:

First of all, we need to determine the horizontal and vertical components of the hockey puck.

For horizontal component of this:

[tex]V^{2}= U^{2}+ 2 as\\V^{2}= 0^{2}+ 2 (9.8)(2)\\V^{2}=39.24\\ V=6.26 m/s[/tex]

For vertical component:

[tex]V_{x}=U_{x} \\V_{x}= 28.0 m/s[/tex]

Now, we can find the angle by using the following formula:

θ= [tex]tan^{-1} =\frac{Vx}{Vy}\\[/tex]

Substituting the values, we get.

Angle = 12.60 degrees.

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The speed and direction of the combined vehicles just after impact is 7.2 m/s west.

The final speed of the cars after the collision is obtained by applying the principle of conservation of linear momentum.

m₁u₁   +   m₂u₂ = v ( m₁ + m₂ )

where;

(1600 x 15.28) - ( 3300 x 18.1) = v ( 1600 + 3300)

-35,282 = 4,900v

v = -35,282  / 4,900

v = -7.2 m/s

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The net force on the proton is 2.88 x 10⁻³⁰ N.

The net electric force between the particles is calculated by applying Coulomb's law as shown below.

F = ( kq₁q₂ ) / r²

where;

The distance between the charges is calculated as;

r = √ [ (-2 - 2)² + ( -4 - 4 )² ]

r = 8.94 m

F = ( 9 x 10⁹ x 1.6 x 10⁻¹⁹ x 1.6 x 10⁻¹⁹ ) / ( 8.94² )

F = 2.88 x 10⁻³⁰ N

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1) They would collide with the walls more frequently.

2) They would collide with the walked more frequently.

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The correct option d. The small divisions at the end of each scale. This allows for the scaling or measurement of a 1'4" distance.

For structures and buildings, architect scales like 1/4" = 1'0" (1/48 size) or 1/8" = 1'0" (1/96 size) are employed.

Thus,  the minuscule divisions at each scale's tip. This makes it possible to scale or measure a 1'4" distance.

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The complete question is-

On the 1/4" = 1'0" architect 's scale, what makes it possible to scale or measure a distance of 1'4"?

Select one:

a. Use the 1/8" scale and convert.

b. Use the 1/16" scale and convert.

c. The large divisions at the end of the scale.

d. The small divisions at the end of each scale.

The force that is acting on the object is 139N. Option A

Let us know that we can only say that there is work done if we have a force that has been applied in such a way that it can be able to move an object in the direction of the force.

As such, we are going to have that;

W = Fcosθ

W = work done

F = force applied

θ = angle turned

1110 = F cos 37 * 10

F = 1110/cos 37 * 10

F =  139N

There is the application of a force of about 139N on the object as have been shown here.

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The Doubling the mass does not affect the period of oscillation.

Oscillation is a repetitive motion that occurs when a force causes an object to move back and forth between two positions. This motion is often seen in physical systems such as pendulums, springs, and electrical circuits.

The period of a block attached to a spring with unknown spring constant is determined by the mass of the block and the spring constant. Doubling the mass of the block will not change the period, so the period will remain 2.7 s. This is because doubling the mass of the block will double both its inertia and its gravitational pull, but these two forces are balanced by the spring force, which remains unchanged. Therefore, doubling the mass does not affect the period of oscillation.

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When a 6.00-g bullet is fired at a target that weighs 10.00 kg and is lying on a frictionless surface at a speed of 96 m/s, the bullet's change in momentum if it penetrates the target is 0.576 m/s.

The momentum change is just equal because the final momentum is zero. Momentum is the phrase used to describe a substance's state of motion when its mass is not zero. Therefore, momentum is a property of all moving objects. The formula p = m v, where m denotes an object's mass and v denotes its rate of motion, describes momentum.

The bullet's momentum will alter and become equal to

momentum = 6/1000 * 96 = 0.576, if it is implanted in the block.

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Answer:

A: Measuring the distance between objects in the ocean

Explanation:

Motion of the bones relative to the three cardinal planes is known as osteokinematic motion, which is resulting from physiological movement.

Osteokinematics describes clear and smooth movements of those bones which are visible from the outside. They are the gross movement that occurs between two bones. They are generated from the rotation around the joint axis. Movement is generaly rotational around the joints.

There are some examples of Osteokinematics are:

Flexion and extension

Abduction and adduction

Lateral rotation and medial rotation

Osteokinematics are different from arthrokinematics. In general Osteokinematics is the bone movement and Arthrokinematics is the joint movement.

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Consider the following explanation for defining surface charge density:

= Q/surface sphere's area.Answers: (a) 5.73 * 10-6 C/m2, (b) 648 * 10 N/C, and (c) 56.5 * 10 3 Nm2/C.

Consider the following explanation for defining surface charge density:

= Q/surface sphere's area

Q thus equals * * 4* * R2.

The new Q is as follows: Q initial -0.5 microC =5 micro C at the outer radius.

The new outside charge on the electric is equal to:

E=k*Q/R2outer=9 109*5 microC/(0.25m)2=648*103 N/C.

Last but not least, the flux equivalent to the internal charge is

The total flux is equal to net change divided by 0 according to Gauss's law.

0.5 microC/0 = 56.5 * 10 3 Nm2/C, therefore.

Answers: (a) 5.73 * 10-6 C/m2, (b) 648 * 10 N/C, and (c) 56.5 * 10 3 Nm2/C.

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The duration of the flight is 3 hours if its speed is reduced by 400 km/h, and the time of flight increased by 60 minutes.

The length of the trip, d = 1200 km

Reduced average speed of the aircraft, v = 400 km/h

Increased time of flight, = 60 minutes = 1 hour

Let the initial time of the flight = t hours

Total time during reduced speed, = (t+1) hours

So, total distance, 1200 km = 400 × (t+1)

t+1 = 1200/400 = 3 hours

So total time of flight is 3 hours.

Initial time of flight, t = 3 - 1 = 2 hours

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The length of the fiber is 75.7 km.

Length is a measurement of distance or size. It is commonly used to describe the linear extent of an object, such as the size of a room, the length of a river, or the size of a person. It can also be used to describe the duration of an event, such as the length of a movie or the length of a football game. Length is typically measured in units such as meters, feet, or inches.

The power at the receiver can be calculated using the formula:

P_r = P_i * 10^(-α*L/10)

where P_r is the power at the receiver, P_i is the input power, α is the attenuation per unit length and L is the length of the fiber.

Rearranging the formula, we obtain:

L = 10*log(P_i/P_r)/α

Substituting the values, we get:

L = 10*log(15/2.4)/0.30 = 75.7 km

Therefore, the length of the fiber is 75.7 km.

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The correct answer is A: thick glass, narrow bore. This design allows the thermometer to have a high sensitivity and to respond quickly to changes in temperature.

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Magntude of the eltric field at radial distances is 12.8a^2.

V = 4/3 r3, where V stands for volume and r for radius, is the equation for a sphere's volume. Half the diameter makes up a sphere's radius.

A conducting sphere has no electric field inside of it. In the same way as a point charge, the electric field outside the sphere is determined by the equation E = kQ/r2. On the outside of the sphere, there is an extra charge.

The curved surface area of the sphere is equal to its entire area because it has a completely curved shape. Alternatively, it is known as lateral surface area. Sphere's radius (r) and its surface area (a) are both expressed as 4r2.

Explanation:

2*2a*2.4a =r =9.6a^2

V = 4/3 *9.6a^2 = 1.3334 * 9.6a^2 = 12.8a^2.

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No. Perhaps the best remedy for a flooded engine is time. Simply open the hood of your car and let excessive fuel evaporate for as long as you can. After about 20 minutes try starting your car again without hitting the gas pedal. If this still does not work, you may have to check your spark plugs.

Why won’t your car start. It turns over, so there’s no problem with the battery, but it won’t fire. Chances are, if you've just started it, moved it a few metres and shut it off again, you've flooded the engine – this is really common as we sometimes want to move a car under the car port, into some shade or into a better parking spot, but without driving it any more than a few metres.

Flooding the engine has nothing to do with water, but the amount of fuel that’s been introduced into the engine. It rarely happens with modern, fuel-injected cars if the temperatures are normal. If it’s cold or very hot it can happen, too.

Don’t keep letting it turn over because you’ll wear out the battery and you’re making the flooding worse (so much so, that you might have so much petrol in the cylinders that it seeps into the oil). Also, don’t pump the accelerator as this can make the flooding worse.

A flooded engine has too much petrol and not enough oxygen. This wets the ends of the spark plugs and they won’t ignite the fuel

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The change in gravitational potential energy is 5.39 J.

Gravitational potential energy is a type of potential energy that an object possesses due to its position in a gravitational field. It is the energy that an object has due to its height and the force of gravity acting upon it. The formula for gravitational potential energy is given by mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object above a reference point. When an object falls from a height, it converts its gravitational potential energy into kinetic energy.

To find the change in gravitational potential energy, we can use the formula: ΔU = mgh, where m is the mass of the object (1.0 kg), g is the acceleration due to gravity (9.8 m/s^2), and h is the change in height.

The change in height is 0.80 m - 0.25 m = 0.55 m. Plugging in the values, we get:

ΔU = 1.0 kg * 9.8 m/s^2 * 0.55 m = 5.39 J

So the change in gravitational potential energy is 5.39 J.

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The complete question is:

A 1.0kg toy car is released at the top of a frictionless track on the left and rolls off of the track from its right side ramp. The car starts at height of 0.80 m, goes through a 0.50 m diameter loop, and exits the ramp at a height of 0.25 m 0.80 m 0.50 mi 0.25 m What is the change in the car's gravitational potential energy from A to B? Round answer to two significant digits.

Electrons from the charged object as conduction are the charging by contact

Conduction is indeed a method of charging by contact. In conduction, charges are transferred between two objects that are in contact with each other. When an uncharged object comes into contact with a charged object, electrons will flow from the charged object to the uncharged object, until both objects have the same charge.

In solids, conduction occurs when electrons flow through the material, moving from atom to atom. Metals, such as copper and aluminum, are good conductors of electricity because their electrons are not tightly bound to their atoms and can easily flow through the material. Insulators, such as rubber and plastic, are poor conductors of electricity because their electrons are tightly bound to their atoms and do not flow easily through the material.

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The painter's gravitational potential energy is 1470J

What is gravitational potential energy?

The energy that a body has or acquires when its location changes as a result of being in a gravitational field is known as gravitational potential energy. Gravitational potential energy can be defined as an energy that has a relation to gravitational force or gravity. Since the painter is on the top of a 3m platform his gravitational potential energy is given by W=mgh where m is the mass of the painter, g is the acceleration due to gravity and h is the height of the painter from the ground.

Now according to the question,

Mass of the painter=50Kg

Height of the platform=3m

Acceleration due to gravity=9.8

W=50×9.8×3

W=1470J

Therefore, the gravitational potential energy of the painter is 1470J

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The electrons are transferred from one item to another during the conduction process.The electrons are particles with a free charge.There is no free movement of protons.

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